# No.1240 (DT)

 No.1240 Dmitri Turevski (Russia) Original Fairy problems JF-10/2017-3/2018: October’2017 – March’2018

 No.1240 Dmitri Turevski Russia original – 05.10.2017 Solutions: (click to show/hide) white Kd3 Rg8 black Pg2e2 Kh3 hs#5.5           2 solutions         (2+3) 1...g2-g1=Q 2.Rg8-g4 Qg1-d1 + 3.Kd3-e3 Kh3-h2 4.Ke3-f2 e2-e1=B + 5.Kf2-f1 Kh2-h1 { }6.Rg4-h4 + Be1*h4 # {(Indian)} 1...g2-g1=R 2.Kd3-e3 Rg1-g4 3.Ke3-f2 Rg4-h4 4.Kf2-g1 e2-e1=S 5.Kg1-h1 Se1-f3 { }6.Rg8-g3 + Kh3*g3 # {(Herlin) (C+ by Popeye 4.79)}

### 8 Responses to No.1240 (DT)

1. dupont says:

Terrific AUW with so few pieces, no fairy piece or condition but lot of moves, congrats Dmitri !

2. seetharaman says:

This is so beautiful !!

3. Ya'aqov Mintz says:

Apparently the first 5-man!!

4. Geoff Foster says:

A terrific find! Either solution would make a good problem on its own. In the first solution 1…g1=Q puts a guard on e3, preventing 2.Ke3??. Then 4…e1=B must be delayed until after 4.Kf2. It is also neat how the bQ guards h5, so the check must be on h4. In the second solution the bR must unguard g1 as quickly as possible, which forces the black move order. Then Black must guard g1, but 4…e1=B? 5.Kh1 Bf2 6.Rg3+ Bxg3!

5. andrew buchanan says:

Very satisfying! Congratulations: this manymover discovery shows the control and flexibility coming from hs# aim.

6. Ya'aqov Mintz says:

AUw theme Record: P0576117

• Joost says:

There’s at least one 3-piece AUW: P1111864.

7. Dmitri Turevski says:

Change the stipulation to zd81 and you can remove both kings 🙂