No.1262 (MC&JML)

Michel Caillaud & Jean-Marc Loustau

Original Fairy problems
October’2017 – March’2018

Definitions: (click to show/hide)

No.1262 Michel Caillaud &
Jean-Marc Loustau


original – 22.12.2017

Solution: (click to show/hide)

white Kf2 Qf3 Sa3 Bb2 Rf4 BHa1h6 RHe8f1 Pc2c6g5 black Kd2 Sa5 Bh4 Gc1d1 RHb7d6e3g3 BHb1e1 Pg6

#2                                             (12+12)
Grasshoppers c1,d1
Rookhoppers e8,f1,b7,d6,e3,g3 Bishophoppers a1,h6,b1,e1
a) Anticircé Calvet
b) Anticircé Cheylan

4 Responses to No.1262 (MC&JML)

  1. Seetharamanseetharaman says:

    Superb !

  2. Kjell Widlert says:

    I love subtle twinning, and this is more subtle than most: not a change from one fairy condition to another, but a change between two forms of the same fairy condition! So the changed play (Lacný) is caused solely by the right for a piece to capture on its own rebirth square: legal or not?

    The mechanism depends on the fact that b1-c1-d1-e1 are rebirth squares both for white attackers and for black defenders (because they are all fairy pieces). So part b (Cheylan) is fairly automatic: Black leaves a thematic square, so White is able to go there (no capture) but Black is unable to defend by going back (with capture). Part a (Calvet), however, has required constructional tricks: the defences must let in other thematic mates according to the Lacný pattern. This has succeeded very well.

    A valuable extra feature is the fact that the two parts have different keys. Naturally, this differentiation is also caused by the difference between Calvet and Cheylan.

  3. Kjell Widlert says:

    (If you read between the lines, you can see that I too find the problem excellent!)

  4. Jacques Rotenberg says:

    a) better than b) but it does not really matter here .
    Can be shown in a less conventional way:
    2# anticirce
    the solution being split in two
    – if you mean “Cheylan”
    – if you mean “Calvet”

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