# Original Problems (32)

## Original Problems (page 32)

Original fairy problems published during 2012 will participate in the informal tourney JF-2012

The site is mostly about fairies, but h# and s# are also welcomed for publication! Please send your problems to my e-mail: julia@juliasfairies.com

### Go to →List of Problems; →Page 31 ;  →Page 33

No.75 – ser-h=2 by Peter Harris – A short, but difficult play, which gives Anti-Super-Circe condition. (JV)

No.76 – ser-h=4 by Peter Harris – This problem is of course more difficult – but the play is far more interesting. (Author)

Definitions:

Circe: Captured units (not Ks) reappear on their game-array squares, of the same colour in the case of pieces, on the file of capture in the case of pawns, and on the promotion square of the file of capture in the case of fairy pieces. If the rebirth square is occupied the capture is normal.

Anti-Super-Circe: After a capture, the side making the capture can place the capturing unit on any empty square. [Placement is compulsory]. A Pawn placed on its first rank is immovable.

Sentinels Pion advers:   When a piece (not a Pawn) moves, a Pawn of the colour of the opposite side appears on the vacated square if it is not on the first or the last rank, and if there are less than 8 Pawns of that colour on the board.

You can сlick on “Solutions” to show or hide the solutions!

 – No.75 Peter Harris South Africa original-08.08.2012 – ser-h=2          b) Sc1→h2         (3+5) Circe Anti-Super-Circe   – Solutions: (click to show/hide) a) 1.d4*c3 [+wQd1][bPc3->c2] 2.e2*d1=R [+wQd1][bRd1->a1] Qd1-g4 = b) 1.d4*c3 [+wQd1][bPc3->b2] 2.Kh1*h2 [+wSg1][bKh2->a1] Sg1*e2 [+bPe7][wSe2->e6] = – I have deliberately made it very short – Ser-H=2. Black makes 2 moves, then White stalemates. I hope this shortness will encourage visitors to solve. (Author) – No.76 Peter Harris South Africa original-08.08.2012 – ser-h=4         2 solutions         (4+4) Circe Sentinels Pion advers Anti-Super-Circe   – Solutions: (click to show/hide) I. 1.Ka1*b1 [+wQd1][bKb1->f2] 2.b2-b1=B 3.Bb1*h7 [+wBf1][bBh7->a1] 4.Kf2*f1=K [+wBf1][bKf1->b2][+wPf2] Bf1-a6 = II. 1.Ka1*b1 [+wQd1][bKb1->b8] 2.a2-a1=R 3.Ra1*d1=R [+wQd1][bRd1->c7] 4.b2-b1=R Qd1*b1 [+bRa8][wQb1->a6] = – This problem is of course more difficult – but the play is far more interesting.(Author)

The diagrams are made on WinChloe and its Echecs font is used for Logo design