No.217 (JM)

 No.217, 217.1, 217.2 János Mikitovics Original Problems, Julia’s Fairies – 2013 (I): January – April →Previous ; →Next ;  →List 2013(I) Please send your original fairy problems to: julia@juliasfairies.com

No.217 – hs=4,5 by János Mikitovics –  Interesting synthesis between strange condition Masand and Circe! (JV)

No.217.1; 217.2 by János Mikitovics –  An improved versions to the problem No.217. (JV)

Definitions:

Masand: A unit which moves and actively checks changes the colour of all the units (not Ks) which it observes after the move. A checking rear (non-moving) piece of a battery would not recolour the units it observes.

Circe:  Captured units (not Ks) reappear on their game-array squares, of the same color in the case of pieces, on the file of capture in the case of pawns, and on the promotion square of the file of capture in the case of fairy pieces. If the rebirth square is occupied the capture is normal.

Chameleon: On completing a move, a Chameleon (from classical standard type) changes into another piece, in the sequence Q-S-B-R-Q…  Promotion may be to a chameleon at any stage in the cycle.

 No.217 János Mikitovics Hungary original-04.01.2013 Dedicated to György Bakcsi   hs=4,5          2 solutions             (2+3)MasandCirce     Solution: (click to show/hide)   I. 1…a2-a1=Q 2.Rg1-e1 [wQa1] + Ke2-d3 3.Re1-e2 d2-d1=B! [bRe2] + 4.Kb3-a3 Kd3-d2 5.Qa1-c3 + Kd2*c3 =   II. 1… d2-d1=Q! [bRg1] + 2.Kb3-b2 Qd1-a1 [wRg1, wPa2] + 3.Kb2*a1 [+Qd8] Qd8-g5 4.Rg1-g2 [wQg5] + Ke2-d1 5.Qg5-d2 [bPa2, bRg2] + Rg2*d2 =   (Py 4.61) No.217.1 János Mikitovics Hungary Version of No.217, 05.01.2013 Dedicated to György Bakcsi   hs=4             2 solutions             (2+3)MasandCirceChameleon Rc2     Solution: (click to show/hide)   I. 1.h7-h8=R! h2-h1=cB! 2.Rh8-h2 [wBh1] + Ke2-d1 3.cBh1-g2=cR cRc2-c4=cQ 4.cRg2-d2=cQ [bRh2] + Rh2*d2 =   II. 1.h7-h8=cQ! h2-h1=cR! 2.cQh8-b2=cS cRh1-b1=cQ 3.cSb2-d1=cB [wRc2] + Ke2-e1 4.cRc2-e2=cQ [bBd1] + Ke1*e2 =
 No.217.2 János Mikitovics Hungary Version of No.217, 07.01.2013 Dedicated to György Bakcsi   hs=4,5        b) wRd1→g1          (2+3)MasandCirce     Solution: (click to show/hide)   a) 1…Ke2-f2 2.Rd1*d2 [+wPd7][wPa2, wPd7] + Kf2-e1 3.Rd2-e2 [bPa2] + Ke1-d1 4.d7-d8=Q+ Kd1-c1 5.Qd8-d1 [bRe2] + Kc1*d1 =   b) 1…d2-d1=Q [bRg1] + 2.Ka1-b2 Qd1-a1 [wRg1, wPa2] + 3.Kb2*a1 [+bQd8] Qd8-g5 4.Rg1-g2 [wQg5] + Ke2-d1 5.Qg5-d2 [bPa2, bRg2] + Rg2*d2 =

7 Responses to No.217 (JM)

1. Seetharaman says:

Very nice. Though the solutions are not a perfect match, the play is interesting and paradoxical. Masand condition actually increases the white force !

• Janos Mikitovics says:

You’re right, the solutions of No.217 are not so harmonic!
I hope that you will like the improved version better!

2. Paul Raican says:

Hi, Janos! The weakness in 217 is that Circe condition is not used in one solution. In 217(1), Circe condition is used only to avoid cooks. Need to search something with Madrasi condition only. Welcome in the fairy world!

3. Janos Mikitovics says:

Hi, Paul! You’re right, the No.217 is a wrong construction! The improved version is a better setting but I hope that I can construct also a more complete variant with the Madrasi or without it. You may make a try too…

• Janos Mikitovics says:

Dear my chess friends Seetharaman and Paul,

many thanks for your useful comments to the No.217 and No.217.1! This is an exciting story of many lessons for me ‘in the fairy world!!’. I hope that the No.217.2 is a real correction of No.217 with active Circe & Masand condicions and you will like it.

Dear Julia,
as a beginner fairy composer thank you very much for your tireless patience and noble loyalty!!

All the best to everyone!
János

• Paul Raican says:

Hi, Janos
Your problem could be arranged as a hs=5 with three solutions
W: Ka1 Rh1 Ph2
B: Ke2 Pa2 Pd2
hs=5 Masand Circe
3 sol.

• Janos Mikitovics says:

Hi, Paul
Yes, but I think the third solution does not harmonize with the other two. (Repetitive moves, unstable circe-condition, + wP on h2, etc.)