# No.265 (JM)

 No.265 János Mikitovics (Hungary) Original Problems, Julia’s Fairies – 2013 (I): January – April ?Previous ; ?Next ; ?List 2013(I) Please send your original fairy problems to: julia@juliasfairies.com

No.265 – János Mikitovics – Non-standard echo-play! (JV)

Definitions:

KoBul Kings: When a piece (not a pawn) of his own side is captured, a King transforms into a Royal piece of the same type as the captured one. When the King is in the form of any Royal piece and there is a capture of one of the pawns of his own side, he becomes a normal King again. ?aptures are illegal if their result is self-che?k because of the transformation of the ?ings according to KoBul rules. Castling is allowed only if the KoBul King is on his initial square in the form of a normal King and if he has not already moved; however he may already have been transformed. In the case of capture by a King in AntiCirce he is reborn on his initial square and may castle. If the capture is by a King which is in the form of some Royal piece, he is reborn on the initial square of that piece.

Chameleon: On completing a move, a Chameleon (from classical standard type) changes into another piece, in the sequence Q-S-B-R-Q…  Promotion may be to a chameleon at any stage in the cycle.

KoKo: A move is possible only if the piece moved arrives on a square next to another unit.

 No.265 János Mikitovics Hungary original-23.02.2013 Dedicated to Diyan Kostadinov   hs#6                                          (1+0+3)b) cQa3?f8 c) nKh4?b1 d) nKh4?d7Chameleon Qa3Kobul KingsKoKo     Solution: (click to show/hide)   a) 1.cQa3-b2=cS nPc3-c2 2.cSb2-d1=cB nPc2-c1=nB 3.cBd1-g4=cR nKh4-g3 4.nKg3-f3 nBc1-f4 5.cRg4-g5=cQ nKf3xf4 [nK=nrB] 6.cQg5-g3=cS nPe7-e5 [nrB=nrB] # b) 1.nPe7-e8=ncB ncBe8-h5=ncR 2.cQf8-b4=cS nKh4-g4 3.ncRh5-f5=ncQ nKg4-f4 4.cSb4-d3=cB nKf4-e3 5.nPc3-c4 nKe3-e2 6.ncQf5-f1=ncS + nPc4xd3 [nrcK=nrcB] # c) 1.cQa3-b3=cS nKb1-c2 2.cSb3-d4=cB nPe7-e5 3.nKc2-d2 nPc3-c2 4.nKd2-d1 nPc2-c1=ncB 5.nKd1-d2 nKd2-c3 6.ncBc1-b2=ncR + nPe5xd4 [nrcK=nrcB] # d) 1.nPe7-e8=ncS ncSe8-d6=ncB 2.cQa3-c5=cS + nKd7xd6 [nrK=nrcB] 3.cSc5-b3=cB nPc3-c2 4.nPc2-c4 nrcBd6-a3=nrcR [nrcB=nrcR] 5.cBb3-a2=cR nrcRa3- c3=nrcQ [nrcR=nrcQ] 6.nrcQc3-a1=nrcS [nrcQ=nrcS] nrcSa1-b3=nrcB [nrcS=nrcB] # Double chameleon echo mates (without symmetric play). (Author)

### One Response to No.265 (JM)

1. Janos Mikitovics says:

Additional twins may be from the d-position.

Examples:

I) nKd7 to f6
II) nKd7 to a4
III) nPc3 to a2
IV) cQa3 to b3 with 2 solutions
V) cQa3 to e2

These are thematic variants, but the first moves are repeated, the nPc3 is not playing in V, etc.