# No.396,397 (PH)

 No.396, 397 Peter Harris (South Africa) Original Problems, Julia’s Fairies – 2013 (III): September- December   →Previous ; →Next ; →List 2013(III) Please send your original fairy problems to: julia@juliasfairies.com

No.396 by Peter Harris – Very interesting roles of the pawns Pg7/Pg2 !  (JV)

No.397 by Peter Harris – Three-man with a bit of surprise !  (JV)

Definitions:

Anti-Circe: After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). R, B & S go to the square of the same colour as the capture; Ps stay on the file of capture.

Anti-Circe (Cheylan): Аs Anti-Circe but the captures on the rebirth squares are forbidden!

Super-Circe – When captured, a piece is reborn on any free field on the chess board without causing self-check or selfmate. Possible is also removal of captured piece from the board. The Pawns (white, black, neutrals, half- neutrals) can be reborn on the first or eight row also. When reborn on the first row  (for Black) or on the eight row (for White) the promotion is obligatory. When reborn on the first row  (for White) or on the eight row (for Black) the Pawns are immovable.

Sentinels Pion Advers:   When a piece (not a Pawn) moves, a Pawn of the colour of the opposite side appears on the vacated square if it is not on the first or the last rank, and if there are less than 8 Pawns of that colour on the board.

 No.396 Peter Harris South Africa original – 23.10.2013   h=2,5                                           (6+9)a) Anti-Circe Cheylan + Super-Circeb) Anti-Circe + Super-Circe     A hint by Author: (click to show/hide) wPg7*bPf8 is very tempting but would waste time and effort. It never happens.   Solutions: (click to show/hide)   a) 1…Kh1-h2 2.f2-f1=R Kh2xg2 [+bPe8][wKg2->e1] 3.b3-b2 Ke1xf1 [+bRb1][wKf1->e1] = b) 1…Ra8xa1 [+bRa8][wRa1->a1] 2.Ra8xc8 [+wSa2][bRc8->a8] + Kh1xg2 [+bPb8][wKg2->e1] 3.b3xa2 [+wSa6][bPa2->a7] Ke1xf2 [+bPe8][wKf2->e1] = (С+ by Popeye 4.63) No.397 Peter Harris South Africa original – 25.10.2013   ser-h=4        b) Kc8 > g4           (0+3)Sentinels Pion AdversAnti-Circe(No white King)     Solutions: (click to show/hide)   a) 1.Ra1-a7 2.Ra7-a6[+wPa7] 3.Ra6-d6[+wPa6] 4.Rd6-d7[+wPd6] a7-a8=R = b) 1.Rh1-h7 2.Rh7-h3[+wPh7] 3.Kg4-h4[+wPg4] 4.Rh3-g3[+wPh3] h7-h8=R = (С+ by Popeye 4.63)

### One Response to No.396,397 (PH)

1. seetharaman says:

397. Nice idea and finales, though underpromotion is easier in Circe or Madrasi. I know it is impossible in this scheme, but it will be great if the other rook moves and replaces the rook that makes lateral moves.