# No.398,399 (PH)

 No.398, 399 Peter Harris (South Africa) Original Problems, Julia’s Fairies – 2013 (III): September- December   →Previous ; →Next ; →List 2013(III) Please send your original fairy problems to: julia@juliasfairies.com

No.398 by Peter Harris – Typical for Peter nice four-men Aristocrat !  (JV)

No.399 by Peter Harris – A melody of pawns in 2 parts !  (JV)

Definitions:

Maximummer – Black must play the geometrically longst move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.

Anti-Andernach: A piece (excluding King) changes its color after any non-capturing move. After capture, the piece retains its color. Rooks on a1, h1, a8 and h8 can be used for castling, provided the usual other rules for that move are satisfied. After castling, Rooks do not change color, If White makes a non-capturing move with neutral or halfneutral piece, that piece becomes black and vice versa.

Chameleon Chess: All pieces on the board which are displayed as orthodox  Q, R, B, S,  are Chameleons. A Pawn can promote only in Chameleon-pieces.

Chameleon: On completing a move, a Chameleon (from classical standard type) changes into another piece, in the sequence Q-S-B-R-Q…  Promotion may be to a chameleon at any stage in the cycle.

Einstein chess: all units (Ks excluded) change their type when they move, according to a precise pattern. For non-capture moves: Q>R, R>B, B>S, S>P, P remains P. For capture-moves: R>Q, B>R, S>B, P>S, Q remains Q.

 No.398 Peter Harris South Africa original – 25.10.2013   h#2,5                2 solutions           (2+2)MaximummerChameleon ChessAnti-Andernach Chess(No white King)     Solutions: (click to show/hide)   1…Sf3-d4=bB 2.Rb7-b1=wQ Qb1-h7=bS 3.Bd4-h8=wR Rh8xh7=Q # 1…Rg1-c1=bQ 2.Qc1-h6=wS Sf3-g5=bB 3.Rb7-h7=wQ Sh6-g4=bB # (С+ by Popeye 4.63) No.399 Peter Harris South Africa original – 26.10.2013   h=4             b) -Pf2; h#6           (0+9)MaximummerEinsteinChessAnti-Andernach Chess(No white King)     Solutions: (click to show/hide)   a) 1.g2-g1=wP g1xh2=S 2.Kd1-e1 Sh2-f1=bP 3.c2-c1=wP c1xb2=S 4.a2-a1=wP Sb2-d1=bP = b) 1.b2-b1=wP b1-b3=bP 2.e2-e1=wP e1xd2=S 3.Kd1-e2 Sd2xb3=B 4.Ke2-f1 Bb3xc2=R 5.Kf1-g1 Rc2xa2=Q 6.h2-h1=wP Qa2xg2 # (С+ by Popeye 4.63 and WinChloe 3.24)