Warm welcome to Eric in Original Problems section of JF!
Original Problems, Julia’s Fairies – 2014 (I): January – April
Please send your original fairy problems to: email@example.com
No.511 by Eric Huber – A nice dedication and complicated to solve three-man in typical Eric’s style! Not long ago I welcomed Eric as a judge of JF-2013/III, but this time I’m happy to welcome his first publication in Original Problems section of JF! (JV)
Maximummer (Black Maximummer): Black must play the geometrically longest move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.
Anti-Circe =Anti-Circe Calvet (the default type): After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). Captures on the rebirth square are allowed. Game array squares are determined as in Circe.
Sentinels Pion Advers: When a piece (not a Pawn) moves, a Pawn of the colour of the opposite side appears on the vacated square if it is not on the first or the last rank, and if there are less than 8 Pawns of that colour on the board.
No.511 Eric Huber
original – 10.03.2014
Dedicated to Peter Harris
b) bKc7->b6; c) bKc7->d6
Sentinels Pion Advers
Hint for solvers: (click to show/hide)
Solutions are not homogeneous.
Solutions: (click to show/hide)
a) 1…Kc7-b6[+wPc7] 2.c7-c8=Q Kb6-a5[+wPb6] 3.Qc8-e6 Ka5-a6[+wPa5] 4.Ka3-b4[+bPa3] a3-a2 5.Qe6-e1[+bPe6] Ka6-b5[+wPa6] #
b) 1…Kb6-a5[+wPb6] 2.b6-b7 b3-b2 3.b7-b8=R b2-b1=R 4.Rb8-b3 Rb1-h1 5.Rb3-b5[+bPb3] + Rh1-a1#
c) 1…Kd6-e5[+wPd6] 2.Ka3-a4[+bPa3] Ke5xd6[bKd6->e8][+wPe5] 3.e5-e6 a3-a2 4.Ka4-a3[+bPa4] a2-a1=S 5.e6-e7 Sa1-c2 #
(C+ by Popeye 4.65/4.63/4.61/4.59 and WinChloe 3.24)
The problem is dedicated to Peter because his amazing 491 brought me to compose it. The only common points between the two problems are the 3 fairy conditions Maximummer, AntiCirce and Sentinels Pion Advers.
All mates are specific. The Maximummer condition forces Black to play the mating move. The Sentinels condition prevents 6.Kc3? in a) or 6.Kb2? in b) and c). The AntiCirce condition prevents the capture of b3/a4 pawns by the white King (wK rebirth would be illegal).