No.598 (KS)

ksoljaNo.598 
Kenneth Solja 
(Finland)

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Original Problems, Julia’s Fairies – 2014 (III): September – December

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Please send your original fairy problems to: julia@juliasfairies.com


No.598 by Kenneth Solja – Interesting start position with Rex Solus! (JV)


Definitions:

Andernach Rook-Lion (or Hurdle Colour Changing Rook-Lion):  hops on Rook-lines over a hurdle changing its color. (In Popeye use: HurdleColourChanging RL).

Andernach Bishop-Lion (or Hurdle Colour Changing Bishop-Lion):  hops on Bishop-lines over a hurdle changing its color. (In Popeye use: HurdleColourChanging BL).

Maximummer: Black must play the geometrically longest move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.


No.598 Kenneth Solja
Finland

original – 13.09.2014

Solutions: (click to show/hide)

White Kb4 Black Sa7 Sb7 Pd4 Black HurdleColourChanging BLD5 RLA2

hs#6         2 solutions           (1+5)
Maximummer
Hurdle colour changing Rook-Lion a2
Hurdle colour changing Bishop-Lion d5
(no black King)


One Response to No.598 (KS)

  1. Paul Rãican says:

    With inverted colors, this problem could be arranged as a helpmate:
    Pieces
    White hurdlecolourchanging BLd5
    White hurdlecolourchanging RLa2
    White Sa7 Sb7 Kf1
    Black Kb4 Pf4
    Stipulation H#6
    Condition WhiteMaximummer
    2 solutions

    1.Kb4-a3 hBLd5-a8[b7=b] 2.Ka3-b2 hBLa8-h1[b7=w] 3.Kb2-b1 hBLh1-a8[b7=b] 4.Sb7-c5 Sa7-b5 5.Kb1-a1 Sb5-c3 6.Sc5-a4 hRLa2-a7[a4=w] #
    1.Kb4-b3 hRLa2-a8[a7=b] 2.Sa7-b5 hBLd5-a2 3.Kb3-a4 hRLa8-a3 4.Ka4-b4 Sb7-a5 5.Kb4-a4 Sa5-c6 6.Sb5-c3 hRLa3-h3[c3=w] #

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