No.602 (PH)

Peter Harris
(South Africa)


Original Problems, Julia’s Fairies – 2014 (III): September – December

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No.602 by Peter Harris – In the beginning there’re just two Kings on the board! (JV)


Isardam: Any move, including capture of the King, is Isardam illegal if a Madrasi-type paralysis would result from it.

Madrasi: Units, other than Kings, are paralysed when they attack each other. Paralysed units cannot move, capture or give check, their only power being that of causing paralysis.

Sentinels: When a piece (Ks included but not pawns) moves, a pawn of the same colour appears on the vacated square unless that square is on the first or eighth ranks or there are 8 pawns of that colour on the board already.

No.602 Peter Harris
South Africa

original – 19.09.2014

Solutions: (click to show/hide)

white Kb7 black Kd2

hs#4         b) wKb7→e4           (1+1)

4 Responses to No.602 (PH)

  1. Seetharamanseetharaman says:

    In general Anti-identical solutions do not appeal to me. But though different both solutions have an underlying logic which is similar and beautiful! It took me sometime to see the reason for 2….Kc4 in the second solution. I think the use of sentinel to pin the king is probably a new idea. Bravo Peter Harris!

    • shankar ram says:

      Keeping the king sitting on a hot potato.. or egg! .. as it where.. and thus preventing him from moving.. is also seen in some other genres.. volcanic Circe.. for example ..

  2. Nikola Predrag says:

    What would be a meaning of “Anti-identity”? “Alter-identity” would be comprehensible.
    Each twin uses a different mechanism and the twinning additionally shows that there are actually two different problems, showing the same idea of a specific Isardam-pin of the Kings by Sentinels.

    While the Sentinels are beautifully used in a), the first two W&B moves produce 4 idle Ps in b). This emphasizes another essential difference between the problems a) and b). a) is hs#4 and b) is an artificially extended hs#2.

    But whoever complains about that, should present it more economically himself . Only the Kings on a diagram and the optimal number of moves in b). 🙂

  3. Kenneth Solja says:

    Well a) has great solution, but I expected b) would be something similar and perhaps with bishops the same idea than what a) was with rooks.

    Otherwise I agree with Nikola here.

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