No.624 (PH)

Peter Harris
(South Africa)


Original Problems, Julia’s Fairies – 2014 (III): September – December

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No.624 by Peter Harris – Two solutions with promotions into all figures and quite different mating pictures. A problem inspired by S.K. Balasubramanian‘s comments to No.621 with a special dedication! (JV)


Sentinels Pion Advers: When a piece (not a Pawn) moves, a Pawn of the colour of the opposite side appears on the vacated square if it is not on the first or the last rank, and if there are less than 8 Pawns of that colour on the board.

Maximummer: Black must play the geometrically longest move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.
White Maximummer: Only White must play the geometrically longest moves, Black plays orthodoxal.

Royal piece: Piece that executes a function of the King on the board.

No.624 Peter Harris
South Africa

original – 14.10.2014
Dedicated to S.K. Balasubramanian.

Solutions: (click to show/hide)

neutral royal ph7 neutral pa7

hs#5                                   (0+0+2n)
Sentinels Pion Advers
Royal piece h7
a) Maximummer
b) White Maximummer

5 Responses to No.624 (PH)

  1. Sebastien Luce says:

    Dear Peter,
    it is very original ! : a lot of action all over the board.
    I like it !

  2. Kjell Widlert says:

    In case you are curious, the false solution from Py 3.69 is
    1.nPa8=nS nSc7 2.nSe8 (+bPc7) nSg7 3.nSf5 (bPg7) nSh4 (+wPf5) 4.nSg6 (+bPh4) c5! (nS~?? illegal) 5.f5*g6+ nrPh5 #,
    which is indeed not even a check to White, it’s just stalemate.

  3. S.K.BalasubramanianS. K. Balasubramanian says:

    Dear Peter Harris,

    Many thanks for your dedication, I doubt whether I really deserve it.
    The moment I saw your 620, I was very much impressed that even with the simplest things you can show very complex ideas. From that time onwards, I started working whether I can add more solutions/phases to your problem. I thought of the following:
    (a) nrBa8, Ser-#6 (b) nrRa8, Ser-#7 (c) nrSa8, Ser-#8
    The intended solutions are:
    (a) 1.nrBc6 2.nrBa8 (+nPc6) 3.nPc7 4.nPc8=nB 5.nBa6 6.nBb7 (+nPa6) #
    (b) 1.nrRa7 2.nrRb7 (+nPa7) 3.nPa8=nR 4.nRa6 5.nrRb8 (+nPb7) 6.nPa7 (+nPa6) 7.nRa8 (+nPa7) #
    (c) Your solution. (unfortunately (b) does not work as the mate can be refuted by 6….nRa8xnPa7!)
    I am happy to see that the idea of Bishop mate has been used very cleverly by you.
    I have a doubt. Is the sentinel pawns created by the movement of a neutral piece in Sentinels Pion Adverse, a neutral pawn or a pawn of opposite colour of the colour assumed on the particular move by the neutral piece?

    — SKB

  4. GanapathiGanapathi says:

    I have also the same doubt as SKB.
    The P created by a sentinel Pion Advers vacation – Is it a neutral P or a P opposite in colour to the moving neutral piece?

    • seetharaman says:

      Simple. When white moves the neutral piece, a black pawn is left, and when moves it, a white pawn is left!

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