# No.742 (SL)

 No.742 Sébastien Luce (France) Original Problems, Julia’s Fairies – 2015 (I): January – June    →Previous ; →Next ; →List 2015(I) Please send your original fairy problems to: julia@juliasfairies.com

No.742 by Sébastien Luce – A new interpretation of Albino theme shown in No.725, but this time with a neutral pawn and a neutral Excelsior in Anti-Circe! (JV)

Definitions:

Anti-Circe: After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). Captures on the rebirth square are allowed. Game array squares are determined as in Circe.

Circe: Captured units (not Ks) reappear on their game-array squares, of the same colour in the case of pieces, on the file of capture in the case of pawns, and on the promotion square of the file of capture in the case of fairy pieces. If the rebirth square is occupied the capture is normal.

 No.742 Sébastien LuceFranceoriginal – 05.03.2015 Solution: (click to show/hide) white kf3 black kh4 rc3d4 pb3b5c4c5d3d5 neutral pc2 ser-#16                            (1+9+1n)Anti-Circe 1.nPc2*b3[nPb3->b2] 2.nPb2*c3[nPc3->c2] 3.nPc2*d3[nPd3->d2] 4.nPd2-d3 { } 5.nPd3*c4[nPc4->c2] 6.nPc2-c3 7.nPc3*d4[nPd4->d2] 8.nPd2-d4 { } 9.nPd4*c5[nPc5->c2] 10.nPc2-c4 11.nPc4-c5 12.nPc5-c6 { } 13.nPc6-c7 14.nPc7-c8=nQ 15.nQc8-e8 16.Kf3-g4 # { (C+ by Popeye 4.69 and WinChloe 3.29)} The promotion in neutral Queen is necessary. In neutral Rook, at the end, black would have the defense 16…Rne1 ! (Author)

### 3 Responses to No.742 (SL)

1. Kjell Widlert says:

The logic behind the sequential albino is worth noting:

1.cxb3 is practically forced. Then 2.bxc3 is necessary, as 3.bxc4? or 3.bxc5? would leave the nP stuck on c2 (because of the “pin” from Rc3). Then 3.cxd3 can and must be played, as 4.cxd4? would leave the nP stuck on d2. Now 5.dxc4 is practically forced, and the next step must be to capture the bR guarding g4. The end is then easy – apart from the elegant trap 14.c8nR? noted by the Composer.

• Kjell Widlert says:

bPb5 remains to be explained. It stops a cook with 1.cxb3 6.b8nQ 8.Kxd4 10.Kf3 11.nQe8 12.Kg4#.

2. Luce Sebastien says:

Thank you Kjell for these clear explanations.
SL