# No.744 (SD)

 No.744 Stephan Dietrich (Germany) Original Problems, Julia’s Fairies – 2015 (I): January – June    ?Previous ; ?Next ; ?List 2015(I) Please send your original fairy problems to: julia@juliasfairies.com

No.744 by Stephan Dietrich – A question: if it is still 100\$ theme in case of 4 moves with Glasgow chess? (JV)

Definition:

Glasgow chess: A pawn promotes on 2nd/7th line.

 No.744 Stephan DietrichGermanyoriginal – 07.03.2015 Solution: (click to show/hide) white Kh5 rb1 pc2g2h2 black ka8 pa7g7 h#4                                            (5+3)Glasgow Chess 1.g7-g5 c2-c4 2.g5-g4 c4-c5 3.g4-g3 c5-c6 4.g3*h2=S c6-c7=S # { (C+ by Popeye 4.69)} 100\$-Theme in 4 moves. (Author)

### 3 Responses to No.744 (SD)

1. Kjell Widlert says:

If we could ask the originators of the idea (Balbus+Rothenberg, I think), they most likely wouldn’t be willing to pay out any dollars…

But this is still an inventive and amusing variation on the theme. With the right conditions, even impossible themes may be easy to show.

2. Stephen Emmerson says:

No of course not. It’s the “\$80 theme”!
Unfortunately for the author, it’s been done before: three times in the same tourney which introduced Glasgow Chess, all three sets of composers finding the same position which is more or less the same, except for the mate taking place on h6, rather than a(h)8.
2 HM Paisley 1996, bernd ellinghoven, Hans Gruber & Hans Peter Rehm; Stephen Emmerson; (also Michael McDowell though oddly his entry was disallowed!); 8/1p5p/7k/K5R1/PP6/8/5P2/8; H#4 Glasgow Chess.

3. Bartel Erich says:

Maybe the first (?) problem with this kind of
100 \$ Variation –> PDB P1285291
by R. Nojek, 4880 Problemkiste (123) VI 1999