# No.954 (SL)

 No.954 Sébastien Luce  (France) Original Problems, Julia’s Fairies – 2015 (II): July – December    →Previous ; →Next ; →List 2015(II) Please send your original fairy problems to: julia@juliasfairies.com

No.954 by Sébastien LuceDynamo fairy condition in Miniature.
The problem is published in memory of the victims of the Bataclan (13-11-2015).
My condolences to the people of France! (JV)

Definitions:

Dynamo: Classical captures are erased. The pieces can move normally but also can “push” or pull on their “lines of action” another piece (target), and stay on place or move in the same way than the target. The piece and the target can go out of the board.

 No.954 Sébastien Luce France original – 17.11.2015 In memory of the victims of the Bataclan (13-11-2015) Solutions: (click to show/hide) White Bb4 Se3 Black Kd4 ser-h#11                                  (2+1) b) Bb4→d5; c) Bb4→f5; d) Se3→a6 Dynamo {For animation of Dynamo condition the solution is re-written in analogy to Circe (pushing replaced with capturing+re-appearing). See the original WinChloe's solution below. (JV)} a) 1.Kd4-e4 2.Ke4-f3 3.Kf3*e3[+wSd3] 4.Ke3*d3[+wSc3] 5.Kd3-c4 6.Kc4-b5 { } 7.Kb5*b4[+wBb3] 8.Kb4*b3[+wBb2] 9.Kb3*b2[+wBb1] 10.Kb2-a1 { } 11.Ka1*b1[bKb1->a1][+wBc1] Bc1-b2 # b) wBb4-->d5 1.Kd4-d3[wBd5->d4] 2.Kd3*e3[bKe3->d3][+wSf3] 3.Kd3-d2[wBd4->d3] { } 4.Kd2-d1[wBd3->d2] 5.Kd1-c2 6.Kc2*d2[+wBe2] 7.Kd2*e2[+wBf2] { } 8.Ke2*f2[+wBg2] 9.Kf2*g2[+wBh2] 10.Kg2-h1 11.Kh1*h2[bKh2->h1][+wBh3] Bh3-g2 # c) wBb4-->f5 1.Kd4-c3 2.Kc3-d2 3.Kd2*e3[+wSf4] 4.Ke3*f4[+wSg5] 5.Kf4*f5[+wBf6] { } 6.Kf5*f6[+wBf7] 7.Kf6-e7[wSg5->f6] 8.Ke7*f7[+wBg7] { } 9.Kf7*g7[+wBh7] 10.Kg7-h8 11.Kh8*h7[bKh7->h8][+wBh6] Bh6-g7 # d) wSe3-->a6 1.Kd4-c4 2.Kc4-b5 3.Kb5-b6[wBb4->b5] 4.Kb6-b7[wBb5->b6] { } 5.Kb7-c8[wSa6->b7] 6.Kc8-d7 7.Kd7-c6 8.Kc6*b6[+wBa6] 9.Kb6-a7 { } 10.Ka7-a8 11.Ka8*b7[bKb7->a8][+wSc6] Ba6-b7 # { (C+ by WinChloe 3.32)} Original solution by WinChloe, no animation: a) 1.Ke4 2.Kf3 3.Ke3(Se3->d3) 4.Kd3(Sd3->c3) 5.Kc4 6.Kb5 7.Kb4(Bb4->b3) 8.Kb3(Bb3->b2) 9.Kb2(Bb2->b1) 10.Ka1 11.(Bb1->c1) Bb2‡ b) 1.Kd3(Bd5->d4) 2.(Se3->f3) 3.Kd2(Bd4->d3) 4.Kd1(Bd3->d2) 5.Kc2 6.Kd2(Bd2->e2) 7.Ke2(Be2->f2) 8.Kf2(Bf2->g2) 9.Kg2(Bg2->h2) 10.Kh1 11.(Bh2->h3) Bg2‡ c) 1.Kc3 2.Kd2 3.Ke3(Se3->f4) 4.Kf4(Sf4->g5) 5.Kf5(Bf5->f6) 6.Kf6(Bf6->f7) 7.Ke7(Sg5->f6) 8.Kf7(Bf7->g7) 9.Kg7(Bg7->h7) 10.Kh8 11.(Bh7->h6) Bg7‡ d) 1.Kc4 2.Kb5 3.Kb6(Bb4->b5) 4.Kb7(Bb5->b6) 5.Kc8(Sa6->b7) 6.Kd7 7.Kc6 8.Kb6(Bb6->a6) 9.Ka7 10.Ka8 11.(Sb7->c6) Bb7‡ (Four corners of black King) In a) black King plays as a "pusher" for white Knight then white Bishop. In b) black King starts to "pull" white Bishop to d2, then it pushs it to h2. In c) black King go back to d2 as to "push" white Knight to g5, then pushs white Bishop to f7 then pulls white Knight in f6. In d) from moves 3 to 5, black King pulls the Bishop then the Knight towards the a8 corner. In all variations, at the 11th move we see a particular effect of this condition : in a), b) c), black King in the corner "pushes without moving" the Bishop and in d) the Knight. (Author)

### 3 Responses to No.954 (SL)

1. Vlaicu Crisan says:

Simply unforgettable!

• Paul Rãican says:

…and a candidate for Wenigsteiner of the year.

• I would not object to having this problem in the preselection of 32. But many years of competition have shown that the competition is always fierce and judges have often very different views on competing problems. That is fine, we are not in a field where the result can be totally objective.