No.1027,1028 (PH)

 No.1027, 1028  Peter Harris (South Africa) Original Problems, Julia’s Fairies – 2016 (I): January – June    →Previous ; →Next ; →List 2016(I) Please send your original fairy problems to: julia@juliasfairies.com

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 No.1027 Peter Harris South Africa original – 26.03.2016 Solutions: (click to show/hide) white kd1 qf3 rg5 black kd2 qf2 hs#2              b) wSg5              (3+2) Chameleon Chess Anti-Andernach Lortap a) 1.Rg5-g1=Q=b {} Kd2-c2 2.Kd1-c1 + Qf2-e2=S=w # b) +wSg5 1.Sg5-e6=B=b {} Be6-h3=R=w 2.Qf3-g2=S=b + Qf2-e3=S=w # { (C+ by Popeye 4.73)} No.1028 Peter Harris South Africa original – 26.03.2016 Solutions: (click to show/hide) white kh8 qh1 rg1h2 black kg2 rd1 h#3              2 solutions            (4+2) White Maximummer Anti-Andernach Lortap 1.Rd1-d4=w {} Rg1-a1=b {} 2.Ra1-a8=w {} Qh1-a1=b + {} 3.Kg2-f1 Ra8*a1 # 1.Kg2*g1 Qh1-b7=b {} 2.Qb7-d7=w {} Rh2-a2=b {} 3.Ra2-b2=w {} Qd7*d1 # { (C+ by Popeye 4.73)}

One Response to No.1027,1028 (PH)

1. seetharaman says:

Peter back in form. He has worked magic with five-men armies!