# No.1053-1055 (PH)

 No.1053-1055  Peter Harris (South Africa) Original Problems, Julia’s Fairies – 2016 (I): January – June    →Previous ; →Next ; →List 2016(I) Please send your original fairy problems to: julia@juliasfairies.com

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 No.1053 Peter Harris South Africa original – 23.04.2016 Solutions: (click to show/hide) white ba8 sa3 black kg1 qd8 h#4.5            2 solutions          (2+2) Circe Chameleon Einstein Chess 1...Ba8-d5=S 2.Qd8*d5[+wBf1] Bf1-c4=S 3.Qd5*c4[+wBf1] Sa3*c4=B[+bSg8] { } 4.Kg1-h1 Bc4*g8=R[+bBc8] 5.Bc8-h3=S Bf1*h3=R[+bBc8] # { }1...Sa3-c4=P 2.Qd8-d5=R c4*d5=S[+bQd8] 3.Qd8*d5[+wBf1] Bf1-g2=S { } 4.Qd5*g2[+wBf1] Bf1*g2=R[+bSg8] + 5.Kg1-h1 Rg2-g1=B # { (C+ by Popeye 4.73)} No.1054 Peter Harris South Africa original – 23.04.2016 Solutions: (click to show/hide) white kf7 re8 pe4 black kd7 rd5h8 h=3             2 solutions          (3+3) Circe Chameleon Chameleon Chess 1.Rh8-h6=Q e4*d5[+bQd8] 2.Qh6-f8=S Kf7*f8 3.Qd8-b8=S Re8*b8=Q {=} 1.Rh8-g8=Q + Kf7*g8 2.Rd5-f5=Q e4*f5 3.Kd7*e8[+wQd1] f5-f6 {= (C+ by Popeye 4.73)} No.1055 Peter Harris South Africa original – 23.04.2016 Solutions: (click to show/hide) white ke2 rf3 sc3 black kg2 qa7 rd3 hs#3          b) Rd3↔Rf3         (3+3) Circe Chameleon Chameleon Chess a) 1.Sc3-e4=B Qa7-h7=S 2.Be4*h7=R[+bBc8] Bc8-f5=R 3.Rf3-f2=Q + Rf5*f2=Q[+wSg1] # b) bRd3<-->wRf3 1.Sc3-a2=B Qa7*a2=S[+wRh1] 2.Rd3-d6=Q Sa2-c1=B 3.Rh1-f1=Q + Rf3*f1=Q[+wSb1] # { (C+ by Popeye 4.73)}