# No.1063 (PH)

 No.1063  Peter Harris (South Africa) Original Problems, Julia’s Fairies – 2016 (I): January – June    →Previous ; →Next ; →List 2016(I) Please send your original fairy problems to: julia@juliasfairies.com

Definitions: (click to show/hide)

 No.1063 Peter Harris South Africa original – 06.05.2016 Solutions: (click to show/hide) white ke6 qa8 ra4 bh7 sg5 black ke4 qh3 re8 bf7 sc7 hs#3               duplex               (5+5) Chameleon Chess Andernach Chess Isardam 1.Sg5-f3=B + Ke4-e3 2.Ra4-a3=Q + Ke3-d4 3.Bh7-e4=R + Sc7-d5=B # 1.Bf7-g8=R + Ke6-f7 2.Qh3-e3=S Kf7-f6 3.Re8-e6=Q + Sg5*e6=bB # { (C+ by Popeye 4.73)} Only the four specific K moves will do. In the final positions: 1. Of the first solution: the wK is in check only from the bQ – not from the bR or bB. The bK cannot escape to e7 because of check from bR. The wR and wB cannot parry the bQ by moving to g4 because of Isardam. 2. Of the duplex solution: the bK is in check only from the wQ – not the wR or wB. The bK cannot move to d4 or f4 because it would in check from the wR. The bK cannot move to d3, because of check from wB. Also, the bS and bB cannot parry the wQ check because the wR would check. (Author)

### 6 Responses to No.1063 (PH)

1. Nikola Predrag says:

This is fantastic! And a brief analysis shows that all pieces make the mechanism, I hope it’s true.

A few facts:
In the first mate, 4.wBf3-g4?? would be a selfcheck by bRe8 anyway. wQs & bBf7 could be removed from the mate.

In duplex, 1.Qe3=bS? Kf6 fails for the lack of tempo in W2. Just for the curiosity, I added wPa3 (for tempo) and there were cooks. Then I tried adding wP to any square and the various cooks have illustrated how delicate is the balance of the construction.
Just try it.

Beautiful and highly educative, thanks Peter!

2. peter harris says:

In the diagram position any non-King moves gives check.

If the AntiAndernach condition also applied, a check could be parried by moving a piece that would change its colour and type to REPLACE the piece giving rise to the check! This parrying move would itself give check! So there can be a sequence of checks. Each move in the sequence would simultaneously parry and check – which is fascinating.

I wrote an article on this idea that appeared in feenschach f-194 July-August 2012 – titled Constellation.

The article featured the following original problem of mine, Con/8, Dedicated to John Rice:

beg pie
whi kc7 qe4 rd7 bg5 sd5
bla ke7 qd8 rb7 bb6 sb5
stip hs#4 opt whi
cond ander antia
chameleonch isa
twi mov e4 d6
end

(a) 1…Bb6-d4=wR + 2.Sd5-b6=bB + Qd8-g8=wS + 3.Rd4-d6=bQ Rb7-b8=wQ + 4.Bg5-c1=bR + Ke7*d7 #
(b) 1…Bb6-a5=wR + 2.Sd5-b6=bB + Qd8-c8=wS + 3.Ra5-a7=bQ Bb6-e3=wR + 4.Sc8-b6=bB + Ke7-d8 #

Of the 14 half-moves 12 are parry/checks.

It would be a miracle if a problem was made with all moves checks.

3. Luce Sebastien says:

Dear Peter,
it is a Great Problem !
I was not familiar with this combination of conditions but
I took a lot of pleasure to understand it.
The begining position is incredible with the two Kings seemingly in check, but in fact no !
And the two solutions are also fantastic, like a miracle !

I am so sorry to add also it is …C+ Winchloe ! 🙂

4. Nikola Predrag says:

A lonely King may be not-in-check only if all four (or none) opponent’s officers observe him, since the complete cycle of Chameleon color-changing transformations is needed for the full check-preventing effect of Isardam.

The question is how the pieces of the initial static W&B (artificial) setups will play.
It’s great in No.1063 that only wQa8 doesn’t move, which suggests that duplex offers a way to avoid “immobility” of too much pieces.

5. seetharaman says:

Very interesting and beautiful problem!

Ganapathi wrote to me a mail with the following comment (which I am quoting).

“Only after the comments appeared, I understood that neither Kings at start was in check! Then going through the solutions ( it was such a great effort) my head got into a spin literally.
As if this is not enough, he is quoting an earlier problem of his using Antiandernach.
Is Peter a composer or a wizard?!”

6. Nikola Predrag says:

Hm, the combination Andernach+Antiandernach is actually simpler than only one of these conditions.
Pieces always change color after moving (capturing or not).