# No.1100,1101 (EB)

 No.1100, 1101  Erich Bartel (Germany) Original Problems, Julia’s Fairies – 2016 (II): July – December    →Previous ; →Next ; →List 2016(II) Please send your original fairy problems to: julia@juliasfairies.com

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 No.1100 Erich Bartel Germany original – 21.07.2016 Solution: (click to show/hide) white Kh1 black DGc2b7 Pg3 ser-s#27                                      (1+3) Circe Equipollents Alphabetic Chess Double Grasshopper c2, b7 (no bK) 1.Kh1-g2 2.Kg2-h3 3.Kh3*g3[+bPf3] 4.Kg3*f3[+bPe3] 5.Kf3-e2 { } 6.Ke2-d1 7.Kd1-c1 8.Kc1*c2[+bDGc3] 9.Kc2-b2 10.Kb2*c3[+bDGd4] { } 11.Kc3*d4[+bDGe5] 12.Kd4-c5 13.Kc5-b6 14.Kb6-a7 15.Ka7*b7[+bDGc7] { } 16.Kb7-c6 17.Kc6-d6 18.Kd6*e5[+bDGf4] 19.Ke5*f4[+bDGg3] 20.Kf4-f3 { } 21.Kf3*e3[+bPd3] 22.Ke3*d3[+bPc3] 23.Kd3*c3[+bPb3] 24.Kc3-d2 { } 25.Kd2-c1 26.Kc1-b1 27.Kb1-a1 b3-b2 # { (C+ by Popeye 4.73)} white king from corner to corner with symmetrical final mate position. (Author) No.1101 Erich Bartel Germany original – 21.07.2016 Solutions: (click to show/hide) white Pe2 black GIb2 GNd4 Nf4 ser-==8                                    (2+1) b) GIb2–>b3 ; c) GIb2–>c6 Circe Equipollents Madrasi Giraffe b2 Gnu d4 Nightrider f4 (no Kings) a) 1.e2-e3 2.e3*d4[+bGNc5] 3.d4*c5[+bGNb6] 4.c5*b6[+bGNa7] { } 5.b6*a7 6.a7-a8=N 7.Na8-c4 8.Nc4*b2 {==} b) bGIb2-->b3 1.e2-e4 2.e4-e5 3.e5-e6 4.e6-e7 5.e7-e8=GI { } 6.GIe8*d4 7.GId4-e8 8.GIe8*f4 {==} c) bGIb2-->c6 1.e2-e3 2.e3*f4[+bNg5] 3.f4*g5[+bNh6] 4.g5*h6 5.h6-h7 { } 6.h7-h8=GN 7.GNh8-f7 8.GNf7*c6 {== (C+ by Popeye 4.73)} four men three times Excelsior each with another fairy promotion. (Author)

### One Response to No.1100,1101 (EB)

1. Bartel Erich says: