# No.1124,1125 (EB)

 No.1124, 1125 Erich Bartel (Germany) Original Problems, Julia’s Fairies – 2016 (II): July – December    →Previous ; →Next ; →List 2016(II) Please send your original fairy problems to: julia@juliasfairies.com

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 No.1124 Erich Bartel Germany original – 14.09.2016 Solutions: (click to show/hide) white Kd6 Pd7e7f7g7, black Kg6 Rd8 Se8 Bf8 Qg8 ser-==6       b) Rd8↔Qg8        (5+5) Circe Chameleon Madrasi RI Alphabetic Chess a) 1.Kd6-e6 2.Ke6-f5 3.e7*f8=Q[+bRh8] 4.f7*e8=R[+bBc8] { } 5.d7*c8=R[+bRa8] 6.g7*h8=Q {==} b) bRd8<-->bQg8 1.Kd6-e6 2.Ke6-f5 3.e7*f8=R[+bRh8] 4.f7*e8=Q[+bBc8] { } 5.d7*c8=R[+bRa8] 6.g7*h8=R {== (C+ by Popeye 4.75)} No.1125 Erich Bartel Germany original – 14.09.2016 Solutions: (click to show/hide) white Kd4 black MGe3 Sa8 ser-s#15        2 solutions         (1+2) Circe Equipollents White Minimummer Marguerite e3 (no bK) 1.Kd4-d3 2.Kd3-d2 3.Kd2-e2 4.Ke2*e3[+bMGe4] 5.Ke3*e4[+bMGe5] { } 6.Ke4*e5[+bMGe6] 7.Ke5-f5 8.Kf5-f6 9.Kf6*e6[+bMGd6] 10.Ke6*d6[+bMGc6] { } 11.Kd6*c6[+bMGb6] 12.Kc6-d6 13.Kd6-d7 14.Kd7-d8 15.Kd8-c8 Sa8-c7 # 1.Kd4-e4 2.Ke4-f4 3.Kf4-f3 4.Kf3*e3[+bMGd3] 5.Ke3*d3[+bMGc3] { } 6.Kd3-d2 7.Kd2-c2 8.Kc2*c3[+bMGc4] 9.Kc3*c4[+bMGc5] 10.Kc4*c5[+bMGc6] { } 11.Kc5*c6[+bMGc7] 12.Kc6-c5 13.Kc5-b5 14.Kb5-a5 15.Ka5-a6 Sa8-b6 # { (C+ by Popeye 4.75)}

### 3 Responses to No.1124,1125 (EB)

1. Bartel Erich says:

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