# No.1135 (AB)

 No.1135  Andrew Buchanan (Hong Kong) Original Problems, Julia’s Fairies – 2016 (II): July – December    →Previous ; →Next ; →List 2016(II) Please send your original fairy problems to: julia@juliasfairies.com

Definition by the author and inventor: (click to show/hide)

 No.1135 Andrew Buchanan Hong Kong original – 02.10.2016 Solution: (click to show/hide) White Ba1 Pb2c1 Black Kh8 Pc4c5d6e7f8h7 h#5                                     (3+7)   C- Chess4E71 1.c4-c2 b2-b3 + 2.c5-c3 b3*c3-c4+ {(ep)} 3.d6-d4 c4*d4-d5+{(ep) }4.e7-e5 d5*e5-e6 + {(ep)} 5.f8-f6 e6*f6-f7 # {(ep) (C- as Chess4E71 is not implemented in any solving program)} Either the current position is a starting position, or White has just played 0. ... b1-b2, from a position with an impossible check which must therefore have been the starting position itself. In either case, none of the Black pawns have ever moved, and so are eligible to make a double move. wPc1 has also never moved. But what of wPb2? We are up in the air as to whether b2-b4 is legal. Clearly we need a convention to cover the pawn double move - see the revised Chess4E71 definition. Under this convention, since we cannot prove that wPb2 has not moved, 1. ... b2-b4? is not permitted, and the only solution is: 1. c4-c2 b2-b3+ 2. c5-c3 b3xc4 ep+ 3. d6-d4 c4xd5 ep+ 4. e7-e5 d5xe6 ep+ 5. f8-f6 e6xf7 ep#. (Author)