No.1166 (IK)

No.1166 
Igor Kochulov 
(Russia)

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Original Problems, Julia’s Fairies – 2016 (II): July – December

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Definition: (click to show/hide)


No.1166 Igor Kochulov
Russia

original – 14.12.2016

Solutions: (click to show/hide)

white Kd1 Be1e2 Rc2 Qd2 Pg4h3 black Ke5 Qg2 Ba2a3 Pe4e6f6

hs#2.5        2 solutions           (7+7)
SAT


4 Responses to No.1166 (IK)

  1. Seetharamanseetharaman says:

    Is it check or not check if there is more than one flight square?

  2. Geoff Foster says:

    @Seetharaman: In SAT it is check if there is one (or more) flight squares. For example, in the first solution Black cannot play 3…Kxe6??, because it would have flights on e7, f7 and e5.

    This problem has reciprocal change of function between wRc2/wBe1 and bBa2/bQg2: First 1…Bb3/Qf1 unpins wRc2/wBe1, which then moves. 2…Qf2/Bc4 closes a line of the wBe1/wRc2, preventing the bK from escaping (3.Rxe6+ Kf4?? [bK has flight on g3]; and 3.Bxf6+ Kd4?? [bK has flight on c5]). Finally the bB/bQ delivers mate.

  3. Hubert Gockel says:

    A little but pleasant detail: the squares bB and qQ visit on their 1st and 2nd moves are neighbours, (b3/c4) and (f2/f1) respectively.

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