No.1178 (KM)

Karol Mlynka


Original Problems, Julia’s Fairies – 2016 (II): July – December

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Definitions: (click to show/hide)

No.1178 Karol Mlynka

original – 30.12.2016
Dedicated to Ján Golha 60*

Solutions: (click to show/hide)

white PPa2h2 black PPb2e4

hs=4            2 solutions             (2+2)
Chameleon Chess
Reverse Pawn a2,h2,b2,e4

2 Responses to No.1178 (KM)

  1. Jan Golha says:

    Karol, thank you for dedication

  2. Juraj LörincJuraj Lörinc says:

    This problem brings into light an interesting question about equivalence of various fairy elements and their combinations. Totally same content can be shown using the following position:

    White Pa7 Ph7
    Black Pb7 Pe5
    Face-to-Face + Chameleon Chess
    C+ by Popeye 4.75

    1.a7-a8=B b7-b6 2.Ba8-e4=R e5-e8 3.Re4-e7=Q e8-h8 4.Qe7-b4=S b6-b5 =
    1.h7-h8=B e5-e4 2.Bh8-c3=R b7-b5 3.Rc3-e3=Q e4-a8 4.Qe3-b3=S b5-b4 =

    Obviously, this version saves one fairy element (no fairy pieces on the board), thanks to reflecting pawn position on the board and choosing other suitable -t- condition. Is there any reason to prefer one of the choices of fairy elements, especially BtB in this case?

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