# No.1197 (AO)

 No.1197 Aleksey Oganesjan (Russia) Original Fairy problems JF – 2017(I): January – June

 No.1197 Aleksey Oganesjan Russia original – 18.03.2017 Solutions: (click to show/hide) white Kg1 Bb2 black Kd3 Rd2 Pb3c2 h=4                                              (2+4) b) Rd2?e2 ; c) bBd2 a) 1.c2-c1=S {!} Kg1-f1 2.Kd3-c2 Kf1-e1 3.Kc2-b1 Ke1*d2 4.Kb1-a2 Kd2*c1 {=} b) bRd2-->e2 1.c2-c1=B {!} Kg1-f1 2.Kd3-c2 Kf1*e2 3.Kc2-b1 Ke2-d1 4.Kb1-a2 Kd1*c1 {=} c) +bBd2 1.c2-c1=R + {!} Kg1-f2 2.Kd3-c2 Kf2-e2 3.Kc2-b1 Ke2*d2 4.Kb1-a2 Kd2*c1 {= (C+ Popeye 4.75)} Miniature with ideal stalemate and threefold Shnoebelen theme. Simply kind of Many-Ways theme: a) Kg1-f1-e1-d2-c1; b) Kg1-f1-e2-d1-c1; c) Kg1-f2-e2-d2-c1. (Author)

### 6 Responses to No.1197 (AO)

1. Ganapathi says:

Very original, I think! Shnoebelen theme brought into normal play (ie other than Retro/PG!

2. Joost says:

Nitpick: It’s ‘Schnoebelen’.

3. Kjell Widlert says:

An economical way of forcing three different wK routes, in turn forcing three different Schnoebelen promotions on c1. Of course, it is impossible to force a Schnoebelen queen without some additional condition…

4. Joost says:

This is basically a ser-#4:
W: Kg1
B: Ka1 Rd2 Pa2 Pc1
ser-#4
(b) Rd2->e2
(c) Rd2=Bd2

(a) Pawn c1 promotes to a knight, then 1. Kf1 2. Ke1 3. Kd2 4. Kc1=
(b) Pawn c1 promotes to a bishop, then 1. Kf1 2. Ke2 3. Kd1 4. Kc1=
(c) Pawn c1 promotes to a rook, then 1. Kf2 2. Ke2 3. Kd2 4. Kc1=

• Aleksey Oganesjan says:

Probably you mean ser-=4 (not ser-#4)?
It looks like a joke problem which usually has a stipulation with 1/2-move, 1/3-move, 1/4-move and etc :)) Such problems often includes unusual chess moves – castling, promotion and en-passant-capture – that consist of some “components”.

In your version the Pawn already executed a move c2-c1 (or b2xc1) but does not yet promote in any piece – so, it would be really say that the Pawn executed 1/2-move 🙂

I think my h=4-problem is “not fully serial”: yes, Black can execute their moves serially regardless of White (c1X-Kc2-Kb1-Ka2) but White cannot execute their moves serially (Kg1-f~-e~-d~xc1) because at first bK must take off control on some squares that need for wK. So I think that the stipation h= is more suitable than ser-= with “jesting” condition like “Completion of bP promotion” 🙂

• Joost says:

Yes, I meant ser-=4.