No.1222 (PH)

No.1222
Peter Harris (South Africa)

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Original Fairy problems
JF – 2017(I): January – June


Definitions: (click to show/hide)


No.1222 Peter Harris
South Africa

original – 03.06.2017

Solutions: (click to show/hide)

white kb8 qc1 pb7 black kg4 qh3 pb3h4

hs#4.5         b) Kb8→a8            (3+4)
Anti-Circe
Isardam


5 Responses to No.1222 (PH)

  1. JuliaJulia says:

    wK is mated by bQb8 in both solutions!

    • Joost de HeerJoost says:

      No, since in a) the black queen doesn’t deliver the check, the black king does.

      • Stephen Emmerson says:

        In fact, in (a) it is double-check (and the Q guards c7).
        Interesting and subtle difference between this finale and the similar s# finale with Isardam only (see Turnbull & Emmerson, The Problemist i/97), or, as in this position which cuts the pawns and some of the moves from above:
        White Kc5 Qg4
        Black Ke6 Qf7
        HS#2.5 (a) Isardam (b) Isardam + AntiCirce
        (a) 1…Ke5 2.Qd4+ Qf6 3.Kd5+ Qd6#
        (b) 1…Qd7 2.Qf4 Qe8 3.Kd6+ Qb8#

  2. peter harris says:

    No Joost and Stephen: in (a) the bK is not checking the wK – for the same reason the wK is not checking the bK.

  3. Stephen Emmerson says:

    Indeed – you’re right! The bK needs to be reborn too. The bK is still necessary to thwart White’s attempts to parry by observing d8 (e.g. Qh5 or Qd2). Apologies to Julia who was right all along!

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