No.1305 (SKB)


S. K. Balasubramanian (India)

Original Fairy problems
July – December’2018

Definition: (click to show/hide)

No.1305 S. K. Balasubramanian

original – 07.07.2018

Solutions: (click to show/hide)

white Kc7 Pa7 black Ka5

h#2              2 solutions           (2+1)

11 Responses to No.1305 (SKB)

  1. SeetharamanSeetharaman says:

    Magic with three !

  2. S.K.BalasubramanianS. K. Balasubramanian says:

    Thank you Seetharaman.

  3. Seetharamanseetharaman says:

    Jacques Rotenberg points out that he sent a similar problem for my Jubilee Tourney. I now regret not including it in my award despite it being such a clear and striking demo of Superguards. Luckily for Bala Jacuqes failed to publish it elsewhere.


  4. S.K.BalasubramanianS. K. Balasubramanian says:

    Sorry Mr. Jacques Rotenberg that your problem did not figure in the award for which I feel you really deserve. Since it was your original idea (though I was unaware of it), if you agree can I ask Ms. Julia to add your name also for the above published problem?

  5. Jacques Rotenberg says:

    No it’s ok!

  6. Jacques Rotenberg says:

    The set play is 1…Kc6 2.Ka6 a8=R/Q#

    • Seetharamanseetharaman says:

      The setplay is there, but dualised and not using the fairy condition. I thought that is why it was ignored by the composer.

  7. S.K.BalasubramanianS. K. Balasubramanian says:

    Dear Jacques,
    Thanks for pointing out the set play which completes AUW.

  8. Nikola Predrag says:

    The dual mate a8R/Q# is exactly opposite to the essence of AUW.

  9. Nikola Predrag says:

    1…a7-a8=S 2.Ka5-a6 Kc7-b6 #
    1…Kc7-c6 2.Ka5-a6 a7-a8=Q #
    1…Kc7-c6 2.Ka5-a6 a7-a8=R #

    1.Ka5-a6 a7-a8=B 2.Ka6-a7 Kc7-b7 #
    1.Ka5-b5 a7-a8=S 2.Kb5-a6 Kc7-b6 #
    With any further comment-avoidance 🙁

  10. S.K.BalasubramanianS. K. Balasubramanian says:

    Thank Nikola. Yes, I agree that AUW cannot be claimed for this setting. It is purely two under promotion problem.

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