# No.1378 (AB)

 No.1378  Aleksandr Bulavka (Belarus) Warm welcome to Aleksandr in Original problems section of JF! Original Fairy problems JF-2019/I: January – June’2019

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 No.1378 Aleksandr Bulavka Belarus original – 24.02.2019 Solutions: (click to show/hide) white Kh5 Sg7 black Ph6 black royal Zh8 =2                                                (2+2) Anchor Ring Anti-Super Circe Royal Zebra h8 1.Sg7-a8! {zz} 1...Zh8-f3 2.Sa8*h6-b7 {=} 1...Zh8-b5 2.Sa8*h6-f1 {=} 1...Zh8-c6 2.Sa8*h6-a2 {=} 1...Zh8-c2 2.Sa8*h6-g6 {=} 1...Zh8-e2 2.Sa8*h6-a6 {=} 1...Zh8-c6 2.Sa8*h6-g2 {=} 1...Zh8-f5 2.Sa8*h6-b1 {=} 1...Zh8-b3 2.Sa8*h6-f7 {= (C+ by WinChloe 3.43)} Zebra-wheel and S-wheel (at destination). The idea is to demonstrate the following fact: on the 8x8 toroidal board, Zebra controls exactly the same squares as S staying four diagonal squares away from it. (Author)

### 6 Responses to No.1378 (AB)

1. Georgy Evseev says:

White king seems unneeded and it even destroys the quality of final positions. It is possible to do implement the idea without it (using a white royal pawn with a promotion key).

It is even possible to double the idea with some Royal dynasty.

• Kjell Widlert says:

Some more changes would be necessary to deal with the defence 1…h5 if the wK is absent. Perhaps bP>h7 and then everything turned 180 degrees (rZa1, Pa2), with a key that puts the wS within reach of a2?

• Georgy Evseev says:

No, on anchor ring the knight always has two ways to attack any square, if at all possible. So, only promotion key will work.

• shankar ram says:

This works:
WPh7, B Royal Zebra b6, BPb7
With key: 1.h8=S!

2. shankar ram says:

1…Zc6 2.Sxh6->a2?
Should be 2.Sxh6->g2!

• Georgy Evseev says:

No, it should have been 1…Ze6