No.1449 (IK)

Igor Kochulov

Original Fairy problems
July – December’2019

Definitions: (click to show/hide)

No.1449 Igor Kochulov

original – 28.09.2019

Solutions: (click to show/hide)

neutral Kc5 black Qc3 Pc4a4 Sa7 Rb8 white Qc1 Pf7 Sc2 Rg1

hs#2.5         2 solutions        (4+5+1)
Neutral Kc5

No.1449.1 Igor Kochulov

version of No.1449 – 31.10.2019

Solutions: (click to show/hide)

neutral kc5 black Qc3 Pc4a4 Ra6b8 white Qc1 Pf7 Sc2 Rg1

hs#2.5         2 solutions        (4+5+1)
Neutral Kc5

7 Responses to No.1449 (IK)

  1. Nikola Predrag says:

    Nicely presentated unique choice of first white move (1…Qh8 2.Qh6?; 1…Rd8 2.Rg6?). Wrong choice would allow Black to block the respective rebirth of a white checking piece.

    In one phase there’s even a deeper thematic layer
    1…Rd8 2.Rg6? Qa5 3.Qg5+ Rd1+! 4.Qd8!?
    where the check/mate to White is uniquely parried by blocking the rebirth of bQ.

    So, for instance, bRa6 instead of bSa7 would add such a layer also to the other phase
    1…Qh8 2.Qh6? Rb5 3.Rg5+ Qa1+! 4.Qh8!?

  2. Joost de HeerJoost says:

    Why is Kd6 not a refutation of the try, making the try useless anyway?

  3. Nikola Predrag says:

    Joost, the try should be written as in my previous post, as a wrong choice of first white move.

  4. Igor Kochulov says:


  5. shankar ram says:

    Julia needs to put a new diagram 1449.1!

Leave a Reply

Your email address will not be published. Required fields are marked *

You can add images to your comment by clicking here.