No.1460 (MR)

Manfred Rittirsch

Original Fairy problems
July – December’2019

Definition: (click to show/hide)

No.1460 Manfred Rittirsch

original – 27.11.2019
In memoriam Dieter Müller

Solutions: (click to show/hide)

white Pd5d3 Kb6 Bb2h5 Rd1 black Ba6h8 Ke3 Qe1 Pd6f4a3 Sa2h2 Rg7h3

h#2.5          2 solutions          (2+12)

6 Responses to No.1460 (MR)

  1. Kjell Widlert says:

    Either wB mates on d4, in which case wPd3 must go (and its guard of e4 be replaced by a black self-block), so that d2 must be temporarily blocked by wR; or wB mates on c5, in which case Pd3 must be guarded (which Rd1 doesn’t do!), and Pa3 must be captured en route so that a7 must be temporarily blocked by bR. The details are different in the two solutions, which is natural in a bi-colour theme like this; the thematical temporary square-blocks are identical. Nice problem!

  2. adrian storisteanu says:

    A duplex-free duplex!

  3. Seetharamanseetharaman says:

    Like this very much! “Cross-party transfer of theme”– white imitating black. Seems a new genre. Very nice

    • Kjell Widlert says:

      Perhaps not a new genre, there are problems with echoed strategy between White and Black. But the terms “duplex-free duplex” and “cross-party transfer of theme” are new to me.

      The form is unusual, perhaps because it is hard to set the idea harmoniously (which Manfred did here!).

  4. Manfred says:

    Kjell is absolutely right: the “cross-party transfer” concept is not new, but exploited very rarely because of implicit challenges. See G179, FA 2010-2012 for an example with reciprocal critical moves.

  5. Luce says:

    Very nice, but Julia it is 6+11 not 2+12 pieces

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