# No.918 (JH)

 No.918 Joost de Heer (Holland) Original ProblemsJF Retro and PG problems 2015-2016    →Previous ; →Next ; →List 2015(II) Please send your original fairy problems to: julia@juliasfairies.com

No.918 by Joost de Heer – Switchback in PG problem!

 No.918 Joost de HeerHollandoriginal – 08.10.2015In memoriam Gligor Denkovski Solution: (click to show/hide) white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8 PG 12.5                                   (14+16) 1.Pf2-f4 Pa7-a5 2.Pf4-f5 Ra8-a6 3.Pf5-f6 Ra6*f6 4.Sg1-f3 Pd7-d6 { } 5.Ke1-f2 Ke8-d7 6. Kf2-g3 Kd7-e6 7. Sf3-g1 Rf6*f1 { } 8. Sg1-h3 Rf1-f6 9. Qd1-g1 Ke6-f5 10. Qg1-a7 Pb7-b6 { } 11. Kg3-f2 Kf5-g6 12. Kf2-e1 Rf6-f2 13. Sh3-g1 {dia (C+ with Euclide 1.01 (Author))} Switchback white king, double switchback white knight. (Author)

### 2 Responses to No.918 (JH)

1. Joost de Heer says:

An earlier version:
3q1bsr/1ppspppp/3p1k2/pr6/7K/7b/PPPPP1PP/RSBR2S1
SPG 12.5

In this version, the knight makes the same switchback twice (Sg1-f3-g1-f3-g1) but it lacks the king switchback, and the knight switchback is more visible (in the published version, the knight doesn’t necessarily have to move to reach the diagram position).

2. seetharaman says:

Double switchback of the knight is very nice!