No.1261 Günther Weeth
Germany
original – 17.12.2017

Solution: (click to show/hide)

white Ke1 Bh4h7 Pe6
black Kb8 Ra4d5 Sf6g1 Pa2a7b7c4c7d4
17 & #1 Proca Retractor (4+11)
AntiCirce

{no animation for Defensive Retractors (JV)}
1.Ke1:Bf2[Ke1]!, Be3f2+ 2.Kb5:Qa5[Ke1], Rd8d5+ (remains pinned until the three move
finale!) 3.Kb4b5, Ra3a4+ 4.Kc3b4, Ra4a3+ 5.Kd2c3, Bf2e3+ 6.Ke1d2, Be3f2+
7.Kb5:Ba6[Ke1], Kc8b8+ 8.Kb4b5, Ra3a4+ 9.Kc3b4, Ra4a3+ 10.Kd2c3, Bf2e3+
11.Ke1d2, Be3f2+ 12.Kb4:Pb5[Ke1]!, Ra3a4+ 13.Kc3b4, Bf2e3+ 14.Ke1d2, Be3f2+
15.Kc6:Ra6[Ke1], 00 0+ 16.Kd5c6, S anyf6+ (bK/bR being unable to uncapture
anything!) 17.Be7h4 – fw.1.Bg6#
idea: decoy of black castling pieces in such a way as to prepare the mating system;
modification of the black balance (see 12 th move) in order to prevent the black castling pieces
to uncapture anything after having uncastled due to the AntiCirce convention saying that
AntiCirce kings and rooks regain their castling right after capturing and going back to their
rebirth squares. (Author)


No.1261.1 Günther Weeth
Germany
version of No.1261 – 16.01.2018

Solution: (click to show/hide)

white Ke1 Se4 Bh4h7 Pe6
black Kb7 Ra4d5 Sf6g1 Pa2a7c2c7d3d4
18 & #1 Proca Retractor (5+11)
AntiCirce

no animation for Defensive Retractors (JV)
1.Ke1:Bf2[Ke1]!, Be3f2+ 2.Kb5:Qa5[Ke1], Rd8d5+ (remains pinned until the three move finale!) 3.Kb4b5, Ra3a4+ 4.Kc3b4, Ra4a3+ 5.Kd2c3, Bf2e3+ 6.Ke1d2, Be3f2+
7.Kb5:Ba6[Ke1], Kc8b8+ 8.Kb4b5, Ra3a4+ 9.Kc3b4, Ra4a3+ 10.Kd2c3, Bf2e3+
11.Ke1d2, Be3f2+ 12.Kb4:Pb5[Ke1]!, Ra3a4+ 13.Kc3b4, Ra4a3+ 14. Kd2c3, Bf2e3+
15.Ke1d2, Be3f2+ 16.Kf5:Re5[Ke1], 00 0+ (bK/bR now being unable to uncapture
anything for blocking square g8!) 17.Kg4f5, S anyf6+ 18.Be7h4 – fw.1.Bg6#
(not 12.Kc4:Pb5[Ke1]?, Qb4a5+!)
IF Black tries to parry 17.Kg4f5 by uncapturing from g8 (Kg8xX[Ke8] or Rg8xXg6[Ra8]), THEN both [bPh7] and [wPh2] must have promoted without capture, as Black has 16 pieces and black Ps have captured all 11 missing white pieces. This is impossible. So Black must retract 17. – Sf6+, after which Black has captured only 10 of the 11 missing white pieces – so [bPh7] can have promoted on h1 or even on g1 after one capture. (But if White does not make the uncapture 12.KxPb5, then Black is free to make an uncapture from g8. This is just the same as in the original version of the problem.) (Kjell Widlert)


No.1261.2 Günther Weeth
Germany
version of No.1261 – 10.03.2018

Solution: (click to show/hide)

white Ke1 Bd4g6 Rf7 Pg4
black Kb7 Ra4d5 Sf6g1 Pa2a7c2c4c7e6
18 & #1 Proca Retractor (5+11)
AntiCirce

no animation for Defensive Retractors (JV)
1.Ke1:Bf2[Ke1]!, Be3f2+ 2.Kb5:Qa5[Ke1], Rd8d5+ (remains pinned until the three move finale!) 3.Kb4b5, Ra3a4+ 4.Kc3b4, Ra4a3+ 5.Kd2c3, Bf2e3+ 6.Ke1d2, Be3f2+ 7.Kb5:Ba6[Ke1], Kc8b8+ 8.Kb4b5, Ra3a4+ 9.Kc3b4, Ra4a3+ 10.Kd2c3, Bf2e3+ 11.Ke1d2, Be3f2+ 12.Kb4:Pb5[Ke1]!, Ra3a4+ 13.Kc3b4, Ra4a3+ 14. Kd2c3, Bf2e3+ 15.Ke1d2, Be3f2+ 16.Kf5:Rg5[Ke1], 00 0+ (bK/bR now being unable to uncapture anything for blocking square g8!) 17.Ke4f5, Sd7f6+ 18.Bf6d4 & fw.1.Rf8#, and 17...., S anyf6+ 18.Bg7d4 & fw.1.Rd7#
RA after 16^{th} move: White has never captured before; wPh2 was captured by a black officer;
bPh7 went without capturing to h1 for promotion. bPg7 cannot have captured wPh2 as then
the retraction of all eight bPP would account for 12 uncaptures.
Note: Pacemaker does not confirm the solution as its program is not made for a retroanalysis
referring to the way the 3 rd rook is here gained.
As to logic: the 12^{th} move shows relative purity of aim when serving two purposes
simultaneously: a) the bQ’s line (5 th rank) is closed and b) the balance is modified. That first
purpose could as well have been achieved by uncapturing with 12.Kb4:Bb5[Ke1] with the
bPd7 promoting on d1 for a bishop.
Idea: decoy of black castling pieces in such a way as to prepare the mating system;
modification of the black balance (see 12^{th} move) in order to prevent the black castling pieces
to uncapture anything after having uncastled due to the AntiCirce convention saying that
AntiCirce kings and rooks regain their castling right after capturing and going back to their
rebirth squares. (Author)


No.1261.3 Günther Weeth
Germany
version of No.1261 – 21.05.2018

Solution: (click to show/hide)

white Ke1 Bd4h5 Rf7 Pe4
black Kb7 Ra4d5 Sf6g1 Pa2a7c2c4c7e6
18 & #1 Proca Retractor (5+11)
AntiCirce Calvet
No forward defence

no animation for Defensive Retractors (JV)
1.Ke1:Bf2[Ke1]!, Be3f2+ 2.Kb5:Qa5[Ke1], Rd8d5+ (remains pinned until the three move
finale!) 3.Kb4b5, Ra3a4+ 4.Kc3b4, Ra4a3+ 5.Kd2c3, Bf2e3+ 6.Ke1d2, Be3f2+
7.Kb5:Ba6[Ke1], Kc8b8+ 8.Kb4b5, Ra3a4+ 9.Kc3b4, Ra4a3+ 10.Kd2c3, Bf2e3+
11.Ke1d2, Be3f2+ 12.Kb4:Pb5[Ke1]!, Ra3a4+ 13.Kc3b4, Ra4a3+ 14. Kd2c3, Bf2e3+
15.Ke1d2, Be3f2+ 16.Kf5:Re5[Ke1], 000+ (bK/bR now being unable to uncapture
anything for blocking square g8!) 17.Kg4f5, S any+ 18.Bc5d4 – fw.1.Rd7#, or 17...., Sd7
f6+ 18.Bc5d4  fw. 1.Rf8#
RA after 16^{th} move: White has never captured before; 10 uncaptures by bPP; wPh2 was
captured by a black officer; bPh7 went without capturing to h1 for promotion. bPg7 cannot
have captured wPh2 as then the retraction of all eight bPP would account for 12 uncaptures.
Type “Calvet” in order to exclude a dual with 16.Kg8:Rh8[Ke1] etc.
Note: Pacemaker does not confirm the solution as its program is not made for a retroanalysis
referring to the way the 3 rd rook is gained.
As to logic: the 12 th move shows relative purity of aim when serving two purposes
simultaneously: a) the bQ’s line (5 th rank) is closed and b) the balance is modified. That first
purpose could as well have been achieved by uncapturing with 12.Kb4:Bb5[Ke1] with the
bPd7 promoting on d1 for a bishop. Yet no logic in terms of structure with a formulated basic
plan and foreplans.
Idea: decoy of black castling pieces in such a way as to prepare the mating system;
modification of the black balance (see 12 th move) in order to prevent the black castling pieces
to uncapture anything after having uncastled due to the AntiCirce convention saying that
AntiCirce kings and rooks regain their castling right after capturing and going back to their
rebirth squares. (Author)

Is 4…a4xXb3(Pb7) impossible for some reason? It looks like balance is not broken.
Looks like a short solution: 5. Xb3 OOO 6. Kd2c3 Bf2e3 7. Ke1d2 Be3f2 8. Kg4xPh3 S~ 9. Be7h4 & 1. Bg6#
Oh wait, the black king isn’t back on c8 yet.
It really looks like a cook (insolubility) to me.
A couple of other remarks:
– Move 15 should be Kc6xRb6[Ke1], not KxRa6.
– The reason Black’s P balance must be modified is that otherwise Black could defend with 16. – Kg8xX~[Ke8] or Rg8xX~[Ra8]. It took me a while to understand this…
BK should be on b7, shouldn’t it?
That’s true, Georgy: bK is on b7 in the composer’s diagram.
Sorry, corrected, bKb7.
Two notes about the last version:
1) NFD must be added;
2) dual: 16.Kc4xRb4(Ke1)! 000 17.Kd5c4 S any 18.Be7h4 & 1.Bg6#
I agree about NFD (=No Forward Defence): without it, Black is allowed after 6.Ke1d2 Be3f2+ to play the forward move c1R#.
But the reported dual seems incorrect: I believe Black can play for example 16. – Rb1b4+ instead of retracting 000. (So it is essential that bRe5 in the author’s solution is incarcerated and cannot retract to e4 or e6.)
16. – Rb1b4+ is impossible: wK is then already in check from bRa4.
Oh sorry: you are right, Paul! There really is a dual. Perhaps the composer can use it instead of his intended continuation?
The version 1261.2 seems to have a dual at the end in both subvariations:
18.Bc5d4 instead of 18.Bg7d4 and 18.Bf6d4, respectively.
(I have informed the composer.)