# No.1340 (KP)

 No.1340 Kostas Prentos (USA) Original Retro & PG problems JF – R2017-18

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 No.1340 Kostas Prentos USA original – 27.10.2018 Solution: (click to show/hide) neutral Ia8b8c8d8e8f8g8h8a7b7c7d7e7f7g7h7a2b2c2d2e2f2g2h2a1b1c1d1e1f1g1h1 SPG & #1                               (0+0+32) b) h1?g5 ; c) c8?h5 32 Undefined pieces Anti-Andernach Masand {no animation for Undefined pieces (JV)} a) 1.d3=b e6=w 2.Bh6=b Qg5=w 3.Qc1=b Bg5=w 4.Bd8=b d2=w 5.e7=b (PG 4½) & 1...Qxd1[b1,c2,d2,e2=b]# b) 1.Sh3=b e6=w 2.Rg1=b Qg5=w 3.e7=b Sf4=w 4.Se6=b Sd8=w (PG 4) & 1.Qxe7[d7,f7,f8=w][e2,d8=b]# c) 1.e3=b d6=w 2.Qh5=b Bg4=w 3.Bd1=b e2=w 4.d7=b (PG 3½) & 1...Qxe2[d1,e7=w][f1,d2,f2=b]# Each twin was tested with Jacobi, also for shorter PGs. (C+) The choice of Anti-Andernach was made with the intention of reaching the standard homebase position for both sides in a PG with undefined pieces. The stipulation of shortest proof game without the number of moves was preferred in order to unify the twins, with no consideration for the solvers. My apologies to those who will purchase cialis online australia venture to solve this problem. (Author)