No.1397 (PR)

No.1397
Paul Rãican
(Romania)

Original Retro & PG problems
JF – R2019-20


Definitions: (click to show/hide)


No.1397 Paul Rãican
Romania

original – 16.04.2019
dedicated to quartzomaniacs

Solution: (click to show/hide)

white Bf1c1 Ke1 Qd1 BPh2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 BPh7g7f7e7d7c7b7a7 Sg8b8 Rh8a8

PG 30                                       (13+16)
Duelist
Berolina Pawns


No.1397.1 Paul Rãican
Romania

version of No.1397 – 29.04.2019
dedicated to quartzomaniacs

Solution: (click to show/hide)

white Bf1c1 Ke1 Qd1 BPh2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 BPh7g7f7e7d7c7b7a7 Sg8b8 Rh8a8

PG 30.5                                    (13+15)
Duelist
Berolina Pawns


No.1397.2 Paul Rãican
Romania

version of No.1397 – 24.06.2019
dedicated to quartzomaniacs

Solution: (click to show/hide)

white Bf1c1 Ke1 Qd1 BPh2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 BPh7g7f7e7d7c7b7a7 Sg8b8 Rh8a8

PG 32                                    (14+16)
Duelist
Berolina Pawns


No.1397.3 Paul Rãican
Romania

version of No.1397 – 30.07.2019
dedicated to quartzomaniacs

Solution: (click to show/hide)

white Bf1c1 Ke1 Qd1 BPh2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 BPh7g7f7e7d7c7b7a7 Sg8b8 Rh8a8

PG 25                                    (11+14)
Duelist
Berolina Pawns


9 Responses to No.1397 (PR)

  1. François Labelle says:

    Cooked by Jacobi “PG demolition mode” in 6h. The first 5.0 moves are the same as the intention.

    1.BPa4 BPb5 2.BPac4 BPbd5 3.BPe4 BPf5 4.BPg4 BPh5 5.BPb4 BPxb4 6.BPh4 BPa3 7.BPg5 BPce5 8.BPh6 BPf4 9.Sf3 BPxf3 10.Qd2 BPg2 11.Qf4 Rxh6 12.Qc7 Ra6 13.Qd7+ Kf7 14.Qc6 BPg5 15.Qd7+ Be7 16.Qc6 Bb4+ 17.BPc3 Bc5 18.BPd4 Bd6 19.BPe5 Bf8 20.BPf6+ Ke7 21.BPcb5 BPf4 22.Qc4 BPe3 23.Qb4+ BPc5 24.Qc4 BPb4 25.Qd4 BPc3 26.Qe5+ Re6 27.Qc7+ Ke8 28.Qb6 Kd7 29.Qd6+ Ke8 30.Qc6+ Ke7

    By the way, some moves of the text solution are missing disambiguation, for example 2.BPc4 BPd5. There is the same problem with the recent 1394 by Nicolas Dupont. A friendly reminder to composers using Jacobi to select the Output language “Py2Web format” and to send the solution in this format to Julia.

  2. Vlaicu Crisan says:

    For those who enjoy PG in Duellist with Berolina Pawns, please try to solve R261 from Problem Paradise 85/2019.

    Michel Caillaud, Vlaicu Crisan & Eric Huber
    rsb1k1s1/8/8/pppppppp/PPPPPPPP/8/3SB3/RSB1K1R1
    (15 + 13) PG 22.0 Berolina Pawn Duelist

    The Ber[o]lin[a] Wall.

  3. François Labelle says:

    1397.1 is cooked using PG demolition mode as well (in 8h this time).

    1.BPef3 BPh5 2.BPg4 BPhf5 3.BPce4 BPd5 4.BPc4 BPb5 5.BPb4 BPxb4 6.BPh4 BPa3 7.BPg5 BPce5 8.BPf6 BPf4 9.Sh3 BPg3 10.Sg5 BPxg2 11.Sf7 BPec5 12.Sxh8 BPd4 13.Sf7 BPe3 14.Sd6+ Bxd6 15.BPb5 Bb4+ 16.BPc3 Bc5 17.BPb4 Bd4 18.BPa5 Bb6 19.Qd4 Bc5 20.Qe5+ Be7 21.Qe6 BPc5 22.Qe5 BPb4 23.Qc3 Bf8 24.Qc6+ Ke7 25.Qd6+ Ke8 26.Qb6 Ke7 27.Qc6 Ra6 28.Qa8 Re6 29.Qc6 Rd6 30.Qc5 BPc3 31.Qc6

    The intention now shows 2.BPac4 BPbd5, but I see that someone removed the disambiguation suggested by Jacobi for 12… BPac5+ and 15… BPce5+, presumably because the alternative move is not check. The established convention is to disambiguate even in this case. One can verify by playing the orthodox game 1. d4 e5 2. dxe5 Ke7 3. Nd2 Ke6 4. a3 Kd5 5. Ndf3+ in any chess-playing program (N=knight).

  4. Paul Rãican says:

    Thank you, Francois! With Jacobi’s help, I found something else even shorter: 1.BPa4 BPb5 2.BPac4 BPbd5 3.BPe4 BPf5 4.BPg4 BPh5 5.BPb4 BPxb4 (till now as in intended solution) 6.BPh4 BPa3 7.BPg5 BPce5 8.BPf6 BPf4 9.Sf3 BPxf3 10.Qe2 BPg2 11.Qh6 BPec5 12.Qxh8 BPd4 13.Qh6 BPe3 14.Qg6+ Ke7 15.Qe8+ Kd6 16.Qb5 Ke7 17.Qc6 BPc5 18.Qb6 BPd4 19.Qa7+! Rxa7 20.BPab5 Rc7 21.BPa6 Rb7 22.BPc3 Rc7 23.BPb4 Rb7 24.BPa5 Rb6 25.BPb5 Rc6 26.BPb7 Rd6 27.BPa8=Q Re6 28.Qc6 Rd6 29.Qc5 BPc3 30.Qc6. Don’t need to say that Jacobi is fantastic.

  5. François Labelle says:

    1397.2 is cooked using PG demolition mode in 42h. The first 8.0 moves are the same as the intention.

    1.BPa4 BPb5 2.BPac4 BPbd5 3.BPe4 BPf5 4.BPg4 BPh5 5.BPb4 BPxb4 6.Kd2 BPa3 7.Kc3 Rh6 8.Kb4 Rb6+ 9.Kc5 Rxb2 10.Qb3 Rd2 11.Qb5+ Kf7 12.Qc6 BPa5 13.Qd6 BPb4 14.Qb6 BPc3 15.Qb2 BPg5+ 16.Kb5 BPf4 17.BPd4 BPe3 18.BPe5 BPf2 19.BPf6+ Ke7 20.Qb4+ Ke8 21.Qd6 Se7 22.Qc7 Sc6 23.Qb7 Sb4 24.Qc7 Sc2 25.Qe5+ Kd7 26.Qe6+ Kc7 27.Qe8 Kb7 28.Qe5 BPc5 29.Qd6 BPd4 30.Qf4 BPe3 31.Qf3 Ra6 32.Qd1 Rd6

    The intention still has missing disambiguation like 2… BPd5. Why not follow the suggestion in my first comment and get this right effortlessly?

  6. Paul Rãican says:

    This situation seems to be a little competition between computer and human brain and this is quite exciting. After some attempts, I obtained this much shorter game: 1.BPa4 BPb5 2.BPac4 BPbd5 3.BPe4 BPf5 4.BPg4 BPh5 5.BPb4 BPxb4 6.Kd2 BPa3 7.Kc3 Rh6 8.Kb4 Rb6+ 9.Kc5 (this move open another perspective) Rxb2 (wK stalemated) 10.Qb3 Rc2 11.Qb5+ Kf7 12.Qc6 (bK stalemated) BPgf6 13.Qe8+ Kg7 14.Qxh5 Sd7+ 15.Kd6 Se5+ 16.Kxe5 BPec5 17.Be2! (tempo) BPd4 18.Bd3 BPxd3 19.Se2 Rxe2 20.Qh3 Re3 21.Qf1 Rh3 22.Qd1 Rh8. Two circuits.
    The last 15 moves checked by Jacobi.

  7. Paul Rãican says:

    Ruined when I checked the last 16 moves: 7.Kc3 Sd7! 8.Kb4 Sb8 9.Kc5 Sd7+ 10.Kd6 Sc5+ 11.Ke5 Sb3 12.BPbd4 Sxd4 13.Bd3 Sf3+ 14.Sxf3 BPgf6 15.Sg5 BPed6 16.Se6 BPc5 17.Sf4 BPd4 18.Sxh5 BPxd3 19.Sg7+ Kd7 20.Se8 Kxe8 21.Be3 Kf7 22.Bc1 Kg7.

  8. Paul Rãican says:

    Here we have also two circuits, but added S Phoenix: 1.BPa4 BPb5 2.BPac4 BPbd5 3.BPe4 BPf5 4.BPg4 BPh5 5.BPb4 BPxb4 6.Kd2 BPa3 7.Kc3 Rh6 8.Kb4 Rb6+ 9.Kc5 Rxb2(wK stalemated) 10.Qb3 Rc2 11.Qb5+ Kf7 12.Qc6 (bK stalemated) BPgf6 13.Qe8+ Kg7 14.Qxh5 (wK stalemated) Sd7+ 15.Kd6 Se5+ 16.Kxe5 BPec5 17.Sd2 BPb4 18.Sb3 BPxb3 19.Ra2 BPb2 20.Ra3 (tempo) BPa1=S!(S Phoenix) 21.Ra2 Rxa2 22.Be2 Rxe2 23.Qh3 Re3 24.Qf1 Rh3 25.Qd1 Rh8.
    Partially tested with Jacobi:
    stip dia 8 pieces white Kb4 Qd1 Ra1h1 Bc1f1 Sb1g1 BPb2f2h2a4c4e4g4 black Ke8 Qd8 Rb6a8 Bc8f8 Sb8g8 BPa3d5f5h5a7c7e7g7
    stip dia 16 pieces white Ke5 Qf1 Rh1 Bc1 Sg1 BPf2h2a4c4e4g4 black Kg7 Qd8 Rh3a8 Bc8f8 Sa1g8 BPb3d5f5f6a7c7
    cond duelist
    cond berolina

  9. François Labelle says:

    1397.3 is cooked using PG demolition mode in 5 days.

    1.BPa4 BPb5 2.BPec4 BPbd5 3.BPbd4 BPxd4 4.BPb3 BPc3 5.Ke2 BPb2 6.Kf3 BPxb1=Q 7.Kf4 Qd3 8.Ke5 Qf3 9.Bd3 Qxd3 10.BPxd3 BPd5 11.BPe4 BPf5 12.Qg4 BPgf6 13.Qg5 BPec5 14.Qe3 BPb4 15.Qc5 BPxb3 16.Qxb5+ Kf7 17.Qe8+ Kg7 18.Qh5 Sd7+ 19.Ke6 Sc5++ 20.Ke5 Se6 21.BPf3 Sc5 22.BPg4 Se6 23.Qh3 Sd4 24.Qf3 Sc2 25.Qd1 Sxa1

    I think that composers compete against the possibilities of chess, not against computers. These cooks are a reminder that the possibilities of chess are a tough adversary, not easily tamed, even with the Duelist condition.

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