No.1439 (AT)

Andreas Thoma (Germany)

Original Retro & PG problems
JF – R2019-20

Definitions: (click to show/hide)

No.1439 Andreas Thoma

original – 13.09.2019 
Klaus Wenda zum 78. Geburtstag gewidmet

Solution: (click to show/hide)

white Ke3 Qc4 Pa6c2e2g2 Rh8 black Ke5 Qb5 Sb1h1 Bd6e4 Rc3h3 Pc5e7g4h5

-5 & s=1                                   (6+12)
Proca Retractor
Anti-Circe Cheylan

7 Responses to No.1439 (AT)

  1. Kjell Widlert says:

    Isn’t this cooked (dualized) by (1.h4xBg5>g2 Bf6-g5+) 2.Kd3-e3 Ba8-e4+ (to cancel checks from Be4, Rc3, and Rh3) 3.Ke3-d3 & forwards 1.Qe6+ Kxe6# (legal as Rxe8?? is illegal due to Sh1; stalemate as Rh8 is pinned by Rc3 and Rh3) ?
    Or am I overlooking something?

  2. Paul Rãican says:

    It isn’t possible 1.Qd4+ as s=1, because Black has 1. …Kc6!

    • Joost de HeerJoost says:

      Perhaps I wasn’t clear: Mirroring the position doesn’t work, because Kjell’s dual would still work: 1. a4xBb5->b2 Bc6-b5+ 2. Ke3-d3 Bh8-d4+ 3. Kd3-e3 and 1. Qd4 Bxd4->c8=

  3. Paul Rãican says:

    Right! On my board, a black Bishop c6 was missing.

  4. JuliaJulia says:

    wPa6 is added by request of Author (to avoid the cook found by Kjell)

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