Мой дебют в WCCI 2010-2012

julia-skating1Мой дебют в WCCI 2010-2012

Это было мое первое участие в WCCI, и, конечно, я и счастлива, и взволнована, и заинтересована во всех результатах…. Каждый может представить!

Я участвовала только в сказках – Fairy section (судьи в порядке их оценок: Juraj Lörinc, Franz Pachl, Petko Petkov, Tadashi Wakashima, Klaus Wenda), место в списке результатов No.21 (счастливое число!), 29.50 пунктов в сумме, вот с этими задачами:

  • No.1 (2; 2.5; 3; 2; 2 -> 6.50JV-34:

Julia Vysotska

KoBulChess TT 2012, AWARD-April-2012
2nd Prize

hs#3         2 solutions       5+5
KoBul Kings 
Grasshopper d3 
Leo c1 
 

Solutions:

(I) 1.Qd4 cxd4 [wrK=rQ] 2.rQd1 LEd2 3.Gd5 + LExd5 [wrQ=rG] # – not 4.rGxd5(bK= brLE)?? – self-check!!

(II)1.Qb3 cxb3 [wrK=rQ] 2.rQg3 LEe3 3.Ga3 + LExa3 [wrQ=rG] # – not 4.rGxa3(bK= brLE)?? – self-check!!

Realization of the KoBul Kings fairy condition with activity of the both KoBul Kings:

– Active phase of the white KoBul King after sacrifice of the white Q -transformation to the Royal Q, which moves to the mating positions.

– Passive phase of the white Kobul King on the mating move – transformation to the Royal G, which has no possible moves to avoid the mate.

– Passive phase of the black KoBul King –  the only possible defense of the white King  (in the Royal G phase) – capture of the mating piece (bLE) – falls because it transforms the black King into Royal LE piece giving the self-check.

Double Ambush – black (Le) + white (rQ); Bristol theme – wG opens lines for the second moves of bLE; ODT; Model mates.


  • No.2 (3; 3; 3; 2; 2.5 -> 8.50) – SELECTED FOR FIDE ALBUM 2010-2012 – JV-61:

Julia Vysotska

Chameleon-50JT 2012 , KobulChess.com
1st Prize

hs#3,5      b) Sd4->e5     (7+6)
Chameleons: Qa1, Bh8
 

Solutions:

a) 1…Sd4-e2 2.e7-e8=cQ cQa1-f6=cS + 3.Ke4-e5 + Kb7-b8 4.cQe8-d7=cS + cSf6*d7=cB #

(try: 1…Sd4-e6? 2.e7-e8=cQ cQa1-f6=cS + 3.Ke4-e5 + Kb7-b8 4.cQe8-d7=cS + cSf6*d7=cB – no mate, 5.Kf5!)

b) 1…Se5-g4 2.e7-e8=Q cBh8-b2=cR 3.Ke4-d4 + Kb7-a6 4.Qe8-b5 + cRb2*b5=cQ #

(try: 1…Se5-c4? 2.e7-e8=Q cBh8-b2=cR 3.Ke4-d4 + Kb7-a6 4.Qe8-b5 + cRb2*b5=cQ – no mate, 5.Kd3!)

 

  • Creation of black reciprocal batteries CS/CB & CR/CQ after critical moves of black Chameleons.
  • Interchange of functions between the both black Chameleons.
  • Thematic tries of black S with Bivalve-theme.
  • Play of two King’s batteries K/B from both sides.
  • White promotions in Q and CQ.

  • No.3 (2; 3.5; 3; 2; 2 -> 7.00) – JV-25:

Julia Vysotska

Best Problems – 2012, No.63 (Jul 3/2012), #2927

hs#3     b) pc4->d3        7+10
Andernach Chess
PAOs: a5, h8, a1
Nightrider c8
VAO h1
 

Solutions:

a) 1.PAa5-a6 Nc8-e4 2.Rf3-f5 Ne4*a6=wN + 3.Rf5-d5 + Bg8*d5=wB #

b) 1.PAa5-a2 Bg8-d5 2.Rf3-e3 Bd5*a2=wB + 3.Re3-e4 + Nc8*e4=wN #

Sacrifices of white PAO (on a2/a6) with the goal: Annihilation + change of color of the black B and N.

Unpins of white Rf3 with Ne4/Bd5; black half-battery play N-B/PAO; creation of black batteries N/VAO and B/VAO.

Model mates after three white pins (2 active and one passive).


  • No.4 (2; 2.5; 2.5; 1; 1.5 -> 6.00) – JV-17:

Julia Vysotska

Orbit – 2012, No 54 (May-2012), F38

h#2        b) Sb3->f4       1+7+4
Grasshoppers: f2, d1; Lions: d8, a7
 

Solutions:

a) 1.Sc1 nGb1 2.Sd3 nGb6# (3.nGd6? 3.nGe3? 3.nLic5? or not also 3.Gb4?)

b) 1.Sg2 nGh2 2.Se3 nGd6# (3.nGb6? 3.nGd3? 3.nLid5? or not also 3.Gf4?)

Creation of neutral anti-batteries (nG/nLi) with 3 tries of a neutral Gs on the mating move in each solution, which gives a self-check, creating a specific anti-batteries. Opening of line (for the nGs) and self-blocks on the black’s second moves.


  • No.5 (1.5; 3; 3; 2.5; 2 -> 7.50)  – JV-30:

Julia Vysotska

The Problemist – 2012, Vol.23 No.11 (Sep-2012), F2990

h#2,5*                         5+5+3
Moa d6; Mao e4
Locusts: a6,b1
 

Solutions:

Set-play: 1.Qf4 nMO×e4+ 2.Kf5 nMOg3‡

1…Ka4 2.Qe7 nMA×d6+ 3.Kf6 nMAe8‡

  • Block of the neutral Locust by the white King; Zilahi theme;
  • Reciprocal transformation of neutral batteries: Initial battery MOA/LO to MAO/LO and initial battery MAO/LO to MOA/LO after reciprocal captures of their forward-pieces.
  • Bi-valve realized by the black Q: line opening for the neutral Mao/Moa, line closing for the neutral Moa/Mao on the mating move. Distant self-block by the black Q.
  • Pins of black Q by the neutral Mao/Moa.

  • No.6 (1.5; 3.5; 3; 1.5; 1.5 -> 6.00) – JV-32:

Julia Vysotska

Tehtäväniekka – 2012, No.2/2012, #3844

h#2,5      2 solutions    2+7+5
Mao b7; Moa b3
Vao b6; Pao a4 
 

Solutions:

(I) 1…nRg1 2.Sa8 nRa1 3.S×b6 nPA×a1‡

(II) 1…nRg8 2.Sc3 nRd8 3.S×a4 nVA×d8‡

  • Zilahi; 
  • selfblocks with simultaneous selfpins of black Sa2/Sc7;
  • change of functions of Sa2 and Sc7;
  • neutral battery VA-MA / PA-MO play with sacrifice of neutral R for VA/PA move; 
  • change of functions of nMOA-b3 and nMAO-b7.

Задачи отсортированы в моем понимании какие лучше, взгляды судей слегка отличаются. Но я очень рада за No.2 –  с моим любимым Хамелеоном (!) – что он попадает в FIDE Album!


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