Оригинальные задачи (93)

Оригинальные задачи (страница 93)

Оригинальные сказочные задачи, опубликованные в течение 2012-ого года, участвуют в неформальном конкурсе JF-2012!

Сайт в основном посвящен сказочному жанру, но h# и s# тоже будут опубликованы! Пожалуйста, присылайте свои произведения на адрес: julia@juliasfairies.com

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No.158 – h#2 – Julia Vysotska  Забавная игра 2-х превращенных пешек, превращения в хамелеонов, Anti-Andernach эффекты.
Мне самой нравится эта задачка, хотя, говоря о темах, тут особо и писать-то не о чем. 🙂  Мне немножко жаль, что не получилось убрать одну фигурку и получить Мередит и еще тот факт, что статический Sg4 (или теоретически это могла бы быть другая фигура) является хамелеоном с единственной целью – разрешить превращение пешки в хамелеона. (JV)


Chameleon: по завершении хода, Хамелеон (классического стандартного типа) меняется на другую фигуру в последовательности Q-S-B-R-Q… Превращения могу быть в Хамелеон на любой стадии цикла.

Anti-Andernach Chess: фигура (кроме короля) меняет цвет по завершении хода, за исключением ходов со взятием. (Или: фигура (кроме короля) меняет цвет в случае хода без взятия.)

You can сlick on “Solutions” to show or hide the solutions!


No.158 Julia Vysotska
h#2                2 solutions            (5+8)
Сhameleon Sg4
Solutions: (click to show/hide)

Все диаграммы сделаны на WinChloe и ее фонт Echecs использован для дизайна Лого.

16 комментариев: Оригинальные задачи (93)

  1. SeetharamanSeetharaman пишет:

    Nice matching promotions and by black and white ! Only weakness: the original chameleon g4 does not move !

    • Nikola Predrag пишет:

      Very nice idea. For active play of original chameleon, extra move is needed and that’s probably not easy. Meredith might be achieved. For instance:
      White chameleon Re7
      White Kh8 Pd7 Pe2
      Black Pa4 Kd4 Pc3 Pd2 Pf2

      • JuliaJulia пишет:

        Oh, wow! 9 pieces instead of my 13 ! And I thought, I’m becoming better in technique! Very slowly becoming it seems.. 🙂
        Nikola’s version, Meredith:
        h#2; antiandernach; 4+5

        1.d2-d1=wcS d7-d8=bcS 2.cSd8-f7=wcB cSd1*f2=cB #
        1.d2-d1=wcB d7-d8=bcB 2.cBd8-a5=wcR cBd1*a4=cR #

        I’m thinking why haven’t I tried something like this? Definitely, I’d be afraid to use wR because of more possible cooks. But I see here’s the opposite situation – less of cooks, and white chameleons guard 2 squares in each solution. Fine!

        What’s about using my static wS-chameleon or wR-chameleon in Nikola’s version – yes, I don’t like it myself, same as Seetharaman, but this is the only option here to allow a promotion into Chameleon-piece!

  2. SeetharamanSeetharaman пишет:

    Very economical reconstruction ! Nice position with only 9 ! Welldone !!

  3. Diyan Kostadinov пишет:

    A nice problem with matched promotions. When I saw it yesterday I was pretty sure that the position can be improved, but after come back at home to try, I saw that Nikola was ready with it… Well done! In my opinion using of static chameleon piece is a weakness, so I think it’s better to use a regular pieces diagram, but the fairy condition “Chameleon chess” to be included.

  4. Diyan Kostadinov пишет:

    By the way the idea can be realised even in miniature form:
    white: Ka8, Qc1, Pf7
    black: Kb4, Pb3, d2, f2
    H#2 b)Pd2-c4 (3+4)
    Anti-Andernach, Chameleon Chess

    Or can be realised in white minimal and Pawns only position:
    white: Kd4, Pd7
    black: Kb4, Pa3, b3, b6, d2, f2
    H#2 b)Pd2-c4 (2+6)
    Anti-Andernach, Chameleon Chess

  5. Petko A.PetkovPETKO PETKOV пишет:

    Yes, there are many ways to improve this interesting problem. Nikola’s position is a step forward in technical attitude. But possible is, for example, a position with 8 pieces only:

    1.d1=wCB h8=bCB 2.CBe5=wCR CBxa4 =wCR#
    1.d1=wCS h8=bCS 2.CSf7=wCB CBxf2=CB#

    A miniature form is possible also, using the twins a) Position – without Pa4; b) Position – Pf2-a4.
    About use of a static Chameleon here – I don’t think that it is a big weekness, through this piece is only a technical component here. Chameleon in such positions, as all other fairy pieces, legalizes the promotion into Chameleon pieces. Therefore, this piece is needed here as thematic factor. On a shortest distance it is practically impossible to use it in thematic role.

    About use of a new condition Chameleon Chess

    It is a not good solution here, because this new condition is rather restrictive – in Chameleon Chess we cannot promote pieces into other figures – here possible are only Chameleon-promotions. With such powerful restriction it is possible to get a better positions, but de facto the play here is different and more primitive. It is very important to remind that in Julia`s problem and in Predrag`s version not only chameleon-promotions are possible but also orthodox promotions! Adding the Chameleon Chess here, we simplify the initial theme to a primitive idea which is very easy to realize.
    A combination between Anti-Andernach and Chameleon Chess is good and fruitful but not in such form. Because the Chameleon Chess is a rather restrictive condition which is easy to realize, a recommended thematic with this condition is different tasks with promotions a la AUW, Babson etc.

  6. Diyan Kostadinov пишет:

    I am completely agree with Mr. Petkov and Julia that without Chameleon Chess there are options to be promoted regular pieces also, but one of the reason to my suggestion was that with this condition we can present the idea with Pawns only position. Personally in this case I prefere it because the choice between Chameleon and Regular piece promotion here do not add nothing in this composition. But of course if this choice was thematic the better will be to be used Chameleon piece (for example as in the excellent problem n.10 on the following link: http://kobulchess.com/en/problems/chameleon-50-jt-2012-originals/128-chameleon-jt-9-10.html )

  7. Nikola Predrag пишет:

    After explanations by Mr. Petkov, passive original chameleon does not seem so bad. I posted the quick example with wcR mostly because it looked promising for extension to h#2,5. I had no time in the afternoon and now I can not make a satisfying progress but it does not look completely impossible.

    The following zero-position shows some possibilities:
    Stipulation H#3
    Condition AntiAndernachChess
    White chameleon Bd8
    White Kh8 Pd7 Pb2 Pe2
    Black Pc7 Pa5 Pa4 Kd4 Pe3 Pd2 Pf2
    Zero Move e3 e7
    Twin Remove b2
    a) bPe3–>e7
    1…cBxe7=cR 2.d1=wcS d8=bcS 3.cSf7=wcB cSxf2=cB#
    b) -wPb2
    1…cBxc7=cR 2.d1=wcB d8=bcB 3.cBg5=wcR cBxa4=cR#

    By the way, n.10 at Kobulchess is indeed amazing! A question which is not important for the quality of that problem but is important for my understanding: Is the mentioned Bivalve-theme present in the solutions or only in tries?
    If only in tries, the solutions would be something like Bivalve avoidance.

    • SeetharamanSeetharaman пишет:

      You are right Nikola. The bivalve effect is in tries only in problem N.10 at Kobulchess. In the solution it is line opening by the black knight with dual avoidance.(and mutual battery creation of course).

      • JuliaJulia пишет:

        Oh, while I was sleeping everything is already explained about my No.10 at KobulChess.com!
        Nikola’s zero-position for those, who likes to see the diagram:
        h#2.5; zeroposition; a) bPe3->e7, b) -wPb2; (5+7)

        a) bPe3–>e7

        1…cBd8*e7=cR 2.d2-d1=wcS d7-d8=bcS 3.cSd8-f7=wcB cSd1*f2=cB #

        b) -wPb2

        1…cBd8*c7=cR 2.d2-d1=wcB d7-d8=bcB 3.cBd8-g5=wcR cBd1*a4=cR #

        I think about it myself too.

        Also after Mr.Petkov’s comment I guess we can try to use AntiAndernach & ChameleonChess conditions and 4 promotions (4 solutions). I’m not sure if I can do it, and your versions are very welcome!

        • Nikola Predrag пишет:

          Zero-position may serve to illustrate the idea but regular twinning will serve better:

          Stipulation H#2,5
          Condition AntiAndernachChess
          White chameleon Bc8
          White Kh8 Pc7 Pb2
          Black Pb6 Pd6 Kc4 Pf4 Pb3 Ph3 Pc2 Pe2
          b) bPd6–>d7
          a) 1…cBxh3=cR 2.c1=wcB c8=bcB 3.cBf5=wcR cBxf4=cR#
          b) 1…cBxd7=cR 2.c1=wcS c8=bcS 3.cSe7=wcB cSxe2=cB#

          Now the original Chameleon plays in the solutions and is not so desperately closed on c8 in the twin. Still, the superfluous wPb2&bPb3 in a) suggest that improvements might be possible.

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