# No.954 (SL)

 No.954 Sébastien Luce  (Франция) Оригинальные задачи, Julia’s Fairies – 2015 (II): июль – декабрь    →Предыдущая ; →Следующая ;   →Список 2015(II) Пожалуйста, присылайте свои оригинальные сказочные задачи на: julia@juliasfairies.com

No.954 – Sébastien Luce – Сказочное условие Dynamo в миниатюре.
Задача публикуется в память о жертвах Батаклана (13-11-2015).
Мои соболезнования народу Франции! (JV)

Определения:

Dynamo: Classical captures are erased. The pieces can move normally but also can “push” or pull on their “lines of action” another piece (target), and stay on place or move in the same way than the target. The piece and the target can go out of the board.

 No.954 Sébastien Luce France original – 17.11.2015 In memory of the victims of the Bataclan (13-11-2015) Solutions: (click to show/hide) White Bb4 Se3 Black Kd4 ser-h#11                                  (2+1) b) Bb4→d5; c) Bb4→f5; d) Se3→a6 Dynamo {For animation of Dynamo condition the solution is re-written in analogy to Circe (pushing replaced with capturing+re-appearing). See the original WinChloe's solution below. (JV)} a) 1.Kd4-e4 2.Ke4-f3 3.Kf3*e3[+wSd3] 4.Ke3*d3[+wSc3] 5.Kd3-c4 6.Kc4-b5 { } 7.Kb5*b4[+wBb3] 8.Kb4*b3[+wBb2] 9.Kb3*b2[+wBb1] 10.Kb2-a1 { } 11.Ka1*b1[bKb1->a1][+wBc1] Bc1-b2 # b) wBb4-->d5 1.Kd4-d3[wBd5->d4] 2.Kd3*e3[bKe3->d3][+wSf3] 3.Kd3-d2[wBd4->d3] { } 4.Kd2-d1[wBd3->d2] 5.Kd1-c2 6.Kc2*d2[+wBe2] 7.Kd2*e2[+wBf2] { } 8.Ke2*f2[+wBg2] 9.Kf2*g2[+wBh2] 10.Kg2-h1 11.Kh1*h2[bKh2->h1][+wBh3] Bh3-g2 # c) wBb4-->f5 1.Kd4-c3 2.Kc3-d2 3.Kd2*e3[+wSf4] 4.Ke3*f4[+wSg5] 5.Kf4*f5[+wBf6] { } 6.Kf5*f6[+wBf7] 7.Kf6-e7[wSg5->f6] 8.Ke7*f7[+wBg7] { } 9.Kf7*g7[+wBh7] 10.Kg7-h8 11.Kh8*h7[bKh7->h8][+wBh6] Bh6-g7 # d) wSe3-->a6 1.Kd4-c4 2.Kc4-b5 3.Kb5-b6[wBb4->b5] 4.Kb6-b7[wBb5->b6] { } 5.Kb7-c8[wSa6->b7] 6.Kc8-d7 7.Kd7-c6 8.Kc6*b6[+wBa6] 9.Kb6-a7 { } 10.Ka7-a8 11.Ka8*b7[bKb7->a8][+wSc6] Ba6-b7 # { (C+ by WinChloe 3.32)} Original solution by WinChloe, no animation: a) 1.Ke4 2.Kf3 3.Ke3(Se3->d3) 4.Kd3(Sd3->c3) 5.Kc4 6.Kb5 7.Kb4(Bb4->b3) 8.Kb3(Bb3->b2) 9.Kb2(Bb2->b1) 10.Ka1 11.(Bb1->c1) Bb2‡ b) 1.Kd3(Bd5->d4) 2.(Se3->f3) 3.Kd2(Bd4->d3) 4.Kd1(Bd3->d2) 5.Kc2 6.Kd2(Bd2->e2) 7.Ke2(Be2->f2) 8.Kf2(Bf2->g2) 9.Kg2(Bg2->h2) 10.Kh1 11.(Bh2->h3) Bg2‡ c) 1.Kc3 2.Kd2 3.Ke3(Se3->f4) 4.Kf4(Sf4->g5) 5.Kf5(Bf5->f6) 6.Kf6(Bf6->f7) 7.Ke7(Sg5->f6) 8.Kf7(Bf7->g7) 9.Kg7(Bg7->h7) 10.Kh8 11.(Bh7->h6) Bg7‡ d) 1.Kc4 2.Kb5 3.Kb6(Bb4->b5) 4.Kb7(Bb5->b6) 5.Kc8(Sa6->b7) 6.Kd7 7.Kc6 8.Kb6(Bb6->a6) 9.Ka7 10.Ka8 11.(Sb7->c6) Bb7‡ (Four corners of black King) In a) black King plays as a "pusher" for white Knight then white Bishop. In b) black King starts to "pull" white Bishop to d2, then it pushs it to h2. In c) black King go back to d2 as to "push" white Knight to g5, then pushs white Bishop to f7 then pulls white Knight in f6. In d) from moves 3 to 5, black King pulls the Bishop then the Knight towards the a8 corner. In all variations, at the 11th move we see a particular effect of this condition : in a), b) c), black King in the corner "pushes without moving" the Bishop and in d) the Knight. (Author)

### 3 комментария: No.954 (SL)

1. Vlaicu Crisan пишет:

Simply unforgettable!

• Paul Rãican пишет:

…and a candidate for Wenigsteiner of the year.

• Juraj Lörinc пишет:

I would not object to having this problem in the preselection of 32. But many years of competition have shown that the competition is always fierce and judges have often very different views on competing problems. That is fine, we are not in a field where the result can be totally objective.