No.1359 (JML)

Jean-Marc Loustau

Оригинальные сказочные
задачи JF-2018/II:
июль – декабрь’2018

Определения: (показать/спрятать)

No.1359 Jean-Marc Loustau

original – 24.12.2018
Dedicated to Vlaicu Crisan

Solutions: (click to show/hide)

White Rg8 Sh7 RNa4 Pf4 Rg4 Ph4 RNg2 Kg1 Black BLh8 RLa6 RLh6 Pd5 Pe5 RNc3 RNf3 Kh3

#2                                             (8+8)
Rook-Lion a6, h6
Bishop-Lion h8
Rose-Lion a4, g2, c3, f3
a) The problem is C+ (says Popeye)
b) The problem is C+ (says Winchloe)

4 комментария: No.1359 (JML)

  1. Kjell Widlert пишет:

    Reciprocal change caused solely by the different implementations in the two solving programs! That’s a very original concept, realized in a very logical mechanism.
    The main effect is that if a white rose-lion can capture its hurdle after a full circle, then a black rose-lion can do the same.

  2. Vlaicu Crisan пишет:

    Dear Jean-Marc, thank you very much for the dedication of this very interesting composition! I simply loved the humorous presentation of the idea, which raised a huge smile on my face.

  3. Jacques Rotenberg пишет:

    it seems that in my winchloe, “une piece ne peut pas capturer son sautoir” exists but the program cannot solve with it !

    • Kjell Widlert пишет:

      The Popeye version can be tested in WinChloe too: there is a fairy piece called “Rose-Lion limitée à 7 bonds” which works just like the Popeye Rose-Lion. Which confirms the author’s statement “there is no condition here, just 2 different kind of fairy pieces”.

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