# No.1338 (KP)

 No.1338 Kostas Prentos (США) Оригинальные Retro & PG задачи JF – R2017-18

Определение: (показать/спрятать)

 No.1338 Kostas Prentos USA original – 21.10.2018 Solution: (click to show/hide) white Bf1c1 Ke1 Qd1 Ph2g2f2e2d2c2b2a2 Sg1b1 Rh1a1 black Bf8c8 Ke8 Qd8 Ph7g7f7e7d7c7b7a7 Sg8b8 Rh8a8 PG 11                                       (11+10) Masand 1.d2-d3 e7-e5 2.Ke1-d2 Qd8-g5[e5=w][g7=w][g2=b]+ 3.Kd2-e1 h7-h5 4.Bc1-f4 Rh8-h6 { } 5.g7*f8=Q[h6=w][f7=w][g8=w]+{+} Ke8*f8 6.e2-e3 g2*f1=Q[g1=b][f2=b][d3=b]+{+ } 7.Ke1*f1 d7-d6 8.Rh1*g1 f2*g1=Q[g5=w][h2=b][e3=b]+ 9.Qg5*g1 { } h2*g1=Q[e3=w][g8=b]+ 10.Kf1*g1 Bc8-g4 11.f7*g8=Q[g4=w][a2=b]+ Kf8*g8 {dia (C+ Jacobi v0.5.2, 10611 sec. (author))} Five promoted Queens are captured on their promotion squares without ever moving (Schnoebelen theme). In orthodox proof games, it is impossible to achieve a Queen Schnoebelen, because there is no way to differentiate the promoted Queen from a Bishop or Rook. With Masand, it is a completely different story: A check by the promoted Queen changes the color of the pieces around her, both orthogonally and diagonally, unlike Rooks or Bishops. In addition, pawns standing close to the promotion squares can be achieved by a change of their color after a check. I had the idea to use the fairy condition Masand with Berolina pawns for Paul Raican’s Murfatlar tourney in Ohrid, earlier this year. Due to lack of free time, I was not able to achieve a worthy example before the deadline and decided to postpone composing for later. After reaching four Queen Schnoebelens with Berolina pawns, I attempted the same with orthodox pawns. It turned out it was possible to improve that task. (Author)

### 4 комментария: No.1338 (KP)

1. Paul Rãican пишет:

Looks like multicolored fireworks. What about two more Q promotions?
12.Be2 dxe2 13.Sc3 exd1=Q [a1,c2=b][d6,h5=w]+ 14.Sxd1 cxd1=Q [a1=w][d6,h5=b]+ 15.Rxd1. The sequence [5.gxf8=Q [h6,f7,g8=w]++ … 13.Sc3] was checked by Jacobi v0.5.3 in about 50 min.

• Paul Rãican пишет:

This last version quickly demolished when I verified the last 5 moves: 10.Kxg1 dxc2 11.Sd2 Bg4 12.Sb1 cxb1=S 13.Rxb1 Bxd1 14.fxg8=Q [a2=b]+ Kxg8 15.Rxd1

• Paul Rãican пишет:

But if the very last promotion is a Rook, then we have a unique sequence:
10.Kxg1 Bg4 11.fxg8=Q [g4=w][a2=b]+ Kxg8 12.Be2 dxe2 13.Sc3 exd1=Q [h5,d6=w][a1,c2=b]+ 14.Sxd1 cxd1=R [a1=w][d6=b]+ 15.Rxd1.

2. Kostas Prentos пишет:

Although it may be possible to achieve more than 5 Queen Schnoebelens in a Masand proof game, having spent several days testing and correcting cooked versions to reach 4 and eventually 5 such cases, I realized that it was not an easy task, at all. Based on all the difficulties I experienced, I didn’t even consider going further.

Is it possible that Paul’s suggestion is sound? Just by looking at the final position, I find it extremely unlikely (the diagram in 14.5 moves can almost be reached in an orthodox massacre PG). Of course, it is practically impossible to test similar positions, even with all the progress made by Jacobi. Common sense is the best guide in this case.