# No.1439 (AT)

 No.1439 Andreas Thoma (Германия) Оригинальные Retro & PG задачи JF – R2019-20

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 No.1439 Andreas Thoma Germany original – 13.09.2019  Klaus Wenda zum 78. Geburtstag gewidmet Solution: (click to show/hide) white Ke3 Qc4 Pa6c2e2g2 Rh8 black Ke5 Qb5 Sb1h1 Bd6e4 Rc3h3 Pc5e7g4h5 -5 & s=1                                   (6+12) Proca Retractor Anti-Circe Cheylan no animation for Defensive Retractors (JV) K/D/T/L/S 1.Bh4×Lg5→g2 Lf6-g5+ 2.Ta8-h8 Lh8-f6+ 3.Kd3-e3 L∼-e4+ 4.a7-a8T La8-∼+ 5.Ke3-d3 & vor: 1.Dc4-e6+ K×D→e8=

### 7 комментариев: No.1439 (AT)

1. Kjell Widlert пишет:

Isn’t this cooked (dualized) by (1.h4xBg5>g2 Bf6-g5+) 2.Kd3-e3 Ba8-e4+ (to cancel checks from Be4, Rc3, and Rh3) 3.Ke3-d3 & forwards 1.Qe6+ Kxe6# (legal as Rxe8?? is illegal due to Sh1; stalemate as Rh8 is pinned by Rc3 and Rh3) ?
Or am I overlooking something?

• Joost пишет:

Could this be fixed by mirroring the position vertically?

• Joost пишет:

No, because 1. Qd4 Bxd4[Bc8] is also possible as s=1.
Perhaps +wPa6.

2. Paul Rãican пишет:

It isn’t possible 1.Qd4+ as s=1, because Black has 1. …Kc6!

• Joost пишет:

Perhaps I wasn’t clear: Mirroring the position doesn’t work, because Kjell’s dual would still work: 1. a4xBb5->b2 Bc6-b5+ 2. Ke3-d3 Bh8-d4+ 3. Kd3-e3 and 1. Qd4 Bxd4->c8=

3. Paul Rãican пишет:

Right! On my board, a black Bishop c6 was missing.

4. Julia пишет:

wPa6 is added by request of Author (to avoid the cook found by Kjell)