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No.709.1 Oliver Sick & |
Original Problems, Julia’s Fairies – 2015 (I): January – June →Previous ; →Next ; →List 2015(I) Please send your original fairy problems to: julia@juliasfairies.com |
No.709, 710 
No.709, 710 by Oliver Sick – Interesting excelsiors with black underpromotions! (JV)
No.709.1 by Oliver Sick & Stephen Emmerson – Nice improvement to No.709, Miniature! (JV)
Definition:
Imitator(I): Every time a piece moves an Imitator (or a set of Imitators) moves simultaneously in an identical manner. An Imitator cannot move of itself. If an Imitator cannot imitate the move of a piece, the move is illegal. An Imitator may only pass through or enter an unoccupied square and cannot move off the board. Castling is imitated by decomposing into a King move followed by a Rook move.
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No.709 Oliver Sick |
Solution: (click to show/hide) |
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White Ka8 Pd6 Ph5 Pf2
Black Kh7 Pb7 Pd7 Ph6
Neutral Ia7
h#5 (4+4) |
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No.709.1 Oliver Sick & |
Solution: (click to show/hide) |
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White Ka6 Pf2
Black Kh7 Pb7 Ph6
Neutral Ia5d3
h#5 (2+3+2i) |
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No.710 Oliver Sick |
Solution: (click to show/hide) |
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White Kg6 Sh7 Ph6 Pf5
Black Ke5 Pe7
Neutral If8
ser-h#13 (4+2) |
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Re 709:
8/1p2p2k/K3P2p/8/8/8/5P2/8/ + Ia5
H#5
saves 1 wP (miniature?) and does not require “No I promotion”
Or:
8/1p5k/K6p/8/8/8/5P2/8/ + Ia5,d3
H#5
saves 3 Ps but adds an I (definitely a miniature now!)
Dear Stephen,
great improvement of my setup, especially the two-imitator version.
I would be very happy to publish it as a cooperation.
Cheers
Oliver
Very nice imitator problems! 709 achieves I think for the first time the 100$ task. That Imitator condition can be used for that is a good find. Stephen’s suggestions are also very good. Since Imitator is a “condition”, even the first suggestion is a miniature !
As Imitator is a very useful condition, I wonder if the task might be achieved through a h#6 without any double step from the thematic Pawns.
Great thinking!
I was just about to write that such a h#6 would always be solvable in 5, when I suddenly saw your point… and of course it is possible!
One sound position is
Ka1 Pe4 f2 – Kh7 Pa4 b7 e6 h6 – Ia3
h#6
1.b6 f3 2.b5 f4 3.b4 f5 4.b3 f6 5.b2 f7 6.b1S(Ia2) f8S(Ia3)#
Not 6.b1R? because of 7.Rh1(Ig3)!,
nor 6.b1B? because of 7.Bd3(Ic5)!,
nor (surprisingly) 6.e5? because of 7.b1I(Ia2)!
… and of course 6.b1I? f8S is not even check – but stalemate for Black.
Well done Kjell, a clear improvement! Popeye’s input/output goes as follows:
BeginProblem
Stipulation h#6
Pieces white Ka1 Pe4f2 black Kh7 Pa4b7e6h6
Cond Imitator a3
EndProblem
1.b7-b6[Ia2] f2-f3[Ia3] 2.b6-b5[Ia2] f3-f4[Ia3] 3.b5-b4[Ia2] f4-f5[Ia3] 4.b4-b3[Ia2] f5-f6[Ia3] 5.b3-b2[Ia2] f6-f7[Ia3] 6.b2-b1[Ia2]=S f7-f8[Ia3]=S #