If you are missing something, then so am I: this must be a fatal dual!
On No.712,713 (SE)
Stephen, the best you can have is probably: a) Ke6 / Kb8 -1(w,b) & h#1 -1.Kd7xRe6 Ra6xQe6 & 1.Ra6-a8 Qe6-b6#…
On No.712,713 (SE)
As Imitator is a very useful condition, I wonder if the task might be achieved through a h#6 without any…
On No.709,710 (OS,SE)
Without the fact that the problem contains 2 same colored-square Bishops, I would obviously never have suggested the possibility to…
On No.711 (PT&CJF)
I will avoid any comments about the content of this original, for quite evident reasons. However, I believe it is…
On No.711 (PT&CJF)
No one mentions it so I'm obviously missing something. What makes a difference between 1...Ra2xQ and 1...Rc7xQ, in No.713?
On No.712,713 (SE)
My point wasn't to just get rid of the other white-walking Bishop, because I know this is possible in Take&Make,…
On No.711 (PT&CJF)
Yes, interesting that (a) involves the same uncaptures as Sunyer too. Incidentally, there is an alternative setting for (b) where…
On No.712,713 (SE)
It was my first formal tourney, I think. I wonder now how I made any sense of such a wide…
On No.712,713 (SE)
712 a-b: Sunyer's problem is quite famous. Fascinating that there are two positions so close to it, with completely different…
On No.712,713 (SE)
