A Rao g5 seems to be missing in the diagram. NB: Happy new year everybody!
On No.1577 (JML)
This is an example of a cook that wouldn't work with 3 TotalInvisibles.
On No.1572 (RJM)
Yes, rich&deep. And the logic of the key can be gradually built through the tries which introduce the refutations that…
On No.1576 (AG&DP)
One of the best Mars Circe direct compositions I have seen in many years. The whole play - including the…
On No.1576 (AG&DP)
I think that in new correction works: 1... Kg1(+wRf1) 2.Bb8 Sc2 3.Ixc2(=K) Ra2+ 4.Kc1 (so second wI is Sd1) Sc3/e3/f2#
On No.1572 (RJM)
Oh, and it just occurs to me that your solutions also work with 3 TotalInvisibles instead of 2+1 Invisibles. This…
On No.1572 (RJM)
Bonjour René I think that your new version is cooked: 1.-Sg2 2.I(K)xg2 I~ 3.Kh1/Kh2 Kf2 4.dxIc2 Rh8# (wI on b6-e3)…
On No.1572 (RJM)
Georgy, see “December 29, 2020 08:54” above: “…in the I-system an IxI-capture is not valid. For more, ask T.Wakashima, the…
On No.1572 (RJM)
Isn't in the correction possible 1...Kg1 2.I- Re1 3.Ixe1 Qf3 4.d2 Qf1# ?
On No.1572 (RJM)
Georgy, in your sequence 3.Ixf1 is necessarily 3.Ke2xf1, implying that 2.I-- is 2.Kd3-e2 or Ke3-e2 (2 initial squares for the…
On No.1572 (RJM)
