# No.1234 (PH)

 No.1234 Peter Harris (South Africa) Original Fairy problems JF – 2017(I): January – June

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 No.1234 Peter Harris South Africa original – 29.06.2017 Solutions: (click to show/hide) white Rh1 black Ke1 Pa2f3 h#3                                              (1+3) b) Pa2→g4 ; c) Ke1→h3 ; d) Rh1→a1 Haaner Chess TransmutedKings Anti-Circe Cheylan Super-Circe Anti-Andernach Chess a) 1.Ke1-e3 Rh1-h8=bR 2.a2-a1=wQ Qa1*h8 [+bRe2][wQh8->d1] { } 3.f3-f2=wP Qd1*e2 [+bRe8][wQe2->d1] # b) bPa2-->g4 1.Ke1-a1 Rh1-h4=bR 2.g4-g3=wP g3*h4 [+bRb2][wPh4->h2] { } 3.Rb2*h2 [+wQe8][bRh2->h8] Qe8*h8 [+bRa2][wQh8->d1] # c) bKe1-->h3 1.Kh3-h6 Rh1-h2=bR 2.a2-a1=wB Ba1-g7=bB { } 3.Bg7-e5=wB Be5*h2 [+bRe8][wBh2->c1] # d) wRh1-->a1 1.Ke1-e2 Ra1*a2 [+bPd1=S][wRa2->h1] 2.f3-f2=wP Rh1-h5=bR { } 3.Sd1*f2 [+wBe8][bSf2->b8] Be8*h5 [+bRd3][wBh5->f1] # { (C+ by Popeye <=4.61; no solutions starting Py 4.63 (JV))}

### 2 Responses to No.1234 (PH)

1. Joost says:

The question is: Is in a) Qe2[+wQd1,+bRe8] a legal move? It all depends on the order of applying the fairy conditions: First Haan, then anticirce: Illegal; first anticirce, then Haan: Legal.

2. Georgy Evseev says:

Formally speaking, in the combination Haan+Anticirce “mate from rebirth square” by Queen or Bishop is impossible.
The piece is not allowed to return back after tentative capture of black King.
So, this is the reason the latest Popeye do not see any solution, I think.

The combination of Haan+Anticirce+Antiandernach is self-locking for queen or bishop mates.