Original Fairy problems
|Anti-Circe:||After a capture the capturing piece (Ks included) must immediately be removed to its game array square (necessarily vacant, else the capture is illegal). Captures on the rebirth square are allowed in Anti-Circe Calvet and not allowed in Anti-Circe Cheylan. Game array squares are determined as in Circe: R, B & S go to the square of the same colour as the capture; Ps stay on the file of capture; fairy pieces go to the promotion square of the file of capture.|
|stipulations||'Proca Retractor','-N & #1'|
|-N & #1:||The stipulation means: retract N moves and than mate in 1.|
|Proca Retractor:||The one of the Defensive Retractors, where White and Black retract (take back) a given number of moves (-n moves), in order to reach a position in which a forward stipulation (e.g. #1, s#1) is met. Given a choice, Black will retract those moves that avoid or delay White’s goal. Unless otherwise stated, Black may defend by mating White through a forward move, if such an opportunity exists after one of Black’s retractions.|
The different kinds of Defensive Retractors only differ in the way uncaptures are handled, of course only legal uncaptures are allowed. In Proca Retractors the retracting side decides, if and what man was uncaptured.
Some introduction by the Author:
This problem has some background.
In the “Chessproblem.ca Bulletin” 7/2015 an article “Wenigsteiner in Proca Retractor AntiCirce” was published by Vlaicu Crişan and Eric Huber. The article ended with a call to break the record achieved by Paul Rãican (-18 & # 1). Three months later, a problem by Alex Levit (-19 & # 1) appeared on JF.
Seeing the problem, I immediately realized that it was a new record. Therefore, the first comment on JF wasn’t unexpected. However, the second comment came as a surprise. It turned out that the new record (-21 & # 1) had moved to Problem Paradise. The next surprise was waiting for me when reading the materials of the Wenigsteinerjahrespreis competition for 2016.
The new record (-23 & # 1) by the same author was published in the next issue of PP.
I have long wanted to return the record to JF. I hope that my task is correct and that I succeeded.
And also the hint for solving – the solution includes the following moves:
3.Ke1×Rd1(+wKe1), 9.Ke4×Bf4(+wKe1), 13.Ke3×Pf4(+wKe1), 17.Kh3×Bg4(+wKe1), 33.Kf7×Qe8(+wKe1)
No. 1524 Dmitrij Baibikov|
original - 22.07.2020
|Solution: (click to show/hide)|
White Ke1 Black Kc5 Pc2g5
-34 & #1 Proca 1+3
--Sorry, no animation for Retractors (JV)
Retract 1.Kd1×Pd2(+wKe1)! c3-c2+ 2.Ke1-d1 d3-d2+ 3.Ke1×Rd1(+wKe1) Rd2-d1+ 4.Kf2×Bg2(+wKe1) Rd1-d2+ 5.Kf1-f2 Ba8-g2++ 6.Ke1-f1 Rd2-d1+ 7.Kf2×Sf1(+wKe1) Rd1-d2+ 8.Ke1-f2 Rd2-d1+ 9.Ke4×Bf4(+wKe1)! Kc6-c5+ 10.Ke3-e4 Bb8-f4++ 11.Kf2-e3 Rd1-d2+ 12.Ke1-f2 Rd2-d1+ 13.Ke3×Pf4(+wKe1)! f5-f4+ 14.Kf2-e3 Rd1-d2+ 15.Ke1-f2 Rd2-d1+ 16.Ke1×Pf2(+wKe1) f3-f2+ 17.Kh3×Bg4(+wKe1) Bh5-g4+ 18.Kg3-h3 Kc7-c6+! (18…Kd6-c6? 19.Kg2-g3 g7-g5+ 20.Kf2-g2 Rd1-d2+ 21.Ke2-f2 Ke7-d6++ 22.Ke1-e2 Rd2-d1+ 23.Kg3×Qf4(+wKe1) Kd8-e7+ 24.Kf2-g3 Rd1- d2+ 25.Ke1-f2 Rd2-d1+ 26.Kf2×Se3(+wKe1) Rd1-d2+ 27.Ke1-f2 Rd2-d1+ 28.Kf7×Qe8(+wKe1) ~+ 29.Ke6-f7 & 1.Kd7# – quick checkmate.) 19.Kg2-g3! g7-g5+ 20.Kf2-g2 Rd1-d2+ 21.Ke1-f2 Rd2-d1+ 22.Kg1×Ph2(+wKe1)! h3-h2+ 23.Kf2-g1 Rd1-d2+ 24.Ke1-f2 Rd2-d1+ 25.Kg1×Qh1(+wKe1) Kd8-c7+ 26.Kf2-g1 Rd1-d2+ 27.Ke1-f2 Rd2-d1+ 28.Kg3×Rg4(+wKe1)! Rf4-g4++ 29.Kf2-g3 Rd1-d2+ 30.Ke1-f2 Rd2-d1+ 31.Kf2×Se3(+wKe1) Rd1-d2+ 32.Ke1-f2 Rd2-d1+ 33.Kf7×Qe8(+wKe1)! ~+ 34.Ke6-f7 & 1.Kd7#.
Two records are in an Anti-Circe Proca defensive retractor: