I think the not so aesthetic Pa2 prevents 1.PAb4 Bb3 2.PAb1 (wI captured on b1) Ra2#. It is perhaps possible…
On
Thanks, Georgy, for your opinion on that. We need all the detection powers that can be used against the Invisibles!
On
Also, thanks for the record of 10 updpdf. I will read the pdf.
On No.675 (RJM)
Thanks René, then I'd have to make it a retro problem, I suppose: "Add 10 Black units, then =1." Would…
On No.675 (RJM)
Mike, In 8/8/8/8/7R/2P2P1s/5K2/5R1k, I can imagine 8 Ps on c4,5,6,7 f4,5,6,7 / S on g1 / B on h2. In…
On No.675 (RJM)
11 is cooked. Returning to the 10 problem. Sorry.
On No.675 (RJM)
Amending that to 11 Black Invisibles (remove Black King). Same solution.
On No.675 (RJM)
Just checking with the rules experts, is Black allowed to play 1.Kb2 (self-check in the visible realm), which establishes at…
On
If anyone is ever to write a treatise on the combined elements of Neutrals+BTB, this example should go in there.…
On No.757 (GF)
I wonder if somebody has done something like this already, though: 8/8/8/8/7R/2P2P1s/5K2/5R1k, =1, 10 Black Invisibles. Solution (if I can…
On No.675 (RJM)
