Kings under "or" over P's in the North give that sideways power to P.
Solved it. I like solving short ones when it's a new genre for me, as this was. An AUW+1 crammed…
You're welcome Mike, I've actually tried to clarify the condition to myself, in the first place. It's up to the…
Thanks, Nikola. Your explanation also confirms my belief that there is a distinction between twins (No. 739 here) and non-twin…
The initial set of data does not give one exact position and even the final position might not be exactly…
I think the not so aesthetic Pa2 prevents 1.PAb4 Bb3 2.PAb1 (wI captured on b1) Ra2#. It is perhaps possible…
Thanks, Georgy, for your opinion on that. We need all the detection powers that can be used against the Invisibles!
Also, thanks for the record of 10 updpdf. I will read the pdf.
Thanks René, then I'd have to make it a retro problem, I suppose: "Add 10 Black units, then =1." Would…
Mike, In 8/8/8/8/7R/2P2P1s/5K2/5R1k, I can imagine 8 Ps on c4,5,6,7 f4,5,6,7 / S on g1 / B on h2. In…