There is still another cook that worked in the initial position as well: 5.RPc1=Q, then 1.a1=B 2.a3 ... 4.a4 5.h1=R…
Very nice imitator problems! 709 achieves I think for the first time the 100$ task. That Imitator condition can be…
Re 709: 8/1p2p2k/K3P2p/8/8/8/5P2/8/ + Ia5 H#5 saves 1 wP (miniature?) and does not require "No I promotion" Or: 8/1p5k/K6p/8/8/8/5P2/8/ +…
Yes. It is also interesting to note that the problem is cooked precisely the way Popeye is buggy - it…
The composer referred on Dec. 21 to my question if part a) isn't unsoluble because of 4. - Rg7(Ia8), but…
Thanks Juraj, it seems everything is now clear: - A checked super-transmuted King must move, using the mobility of the…
> the exact definition of supertransmuting kings (Pressburg kings) seems elusive. Can somebody from Pressburg (i.e. Bratislava) or somebody else…
Cook 1.Sd5 ... 5.RPc2, then 1.a1=B 2.h1=R ... 5.Ra2 6.a3 ... 8.a4 ... 14.Kb2 ... 18.h1=R,Q 19.R,Qd1 RPxd1=Q=
Oh dear, you are right of course. That's why the Proca-retro composers say that White must not start the pendulum…
I think the intended solution doesn't work. The pendulum actually starts earlier, after 2nd white move, with wKh5 and bSg7.…