add wKe2 1.Ke2-d3[+bPe2] e2-e1=S=w 2.Se1-c2=b Sc2-a3=w[+wPc2] 3.Sa3-b5=b[+bPa3] Sb5-c3=w[+wPb5] 4.Sc3-b1=b[+bPc3] Sb1-d2=w 5.Sd2-b1=b[+bPd2] d2-d1=Q=w 6.Qd1-h5=b Qh5*b5[bQb5->d8][+wPh5] # 1.Ke2-d3[+bPe2] e2-e1=S=w 2.Se1-c2=b Sc2-a3=w[+wPc2] 3.Sa3-b5=b[+bPa3]…
On No.491 (PH)
Georgy, of course, the version h#4/2x can be our joint problem, if you like it. I would be happy if…
On No.490 (JM)
Yes, you're right Georgy, but the play differs from the original thought because of the repetition and sequence of promotions.…
On No.490 (JM)
Thanks Seetharaman & Diyan.
On No.487 (SKB)
And of wBe8 in 2nd?
On No.489 (KM)
What's the purpose of wSc4 in the 1st mate?
On No.489 (KM)
Nice problem. The solutions may not be difficult, especially the first two.! I like the differenciation of the two rook…
On No.489 (KM)
I remember our Parthasarathy 's a two part article (in our good old magazine "Crosscheck") on the non-thematic uses of…
On No.483,484 (TP)
Excellent problem with rich thematic content!
On No.487 (SKB)
The solutions are practically identical, but the position is economical and the forced mate is good.
On No.486 (KG)
