praicanNo.1184
Paul Rãican
(Romania)

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Original Retro & PG problems
JF – R2017-18


Definitions: (click to show/hide)


No.1184 Paul Rãican
Romania

original – 04.02.2017
In the memory of W. Dittmann

Solution: (click to show/hide)

white Kc2 Sg1 Rh1 black Kg5 Bc3 Pd4g3

-9 & s#1    Proca Retractor       (3+4)
Anti-Circe


No.1184.1 Paul Rãican
Romania

version of No.1184 – 22.04.2017
In the memory of W. Dittmann

Solution: (click to show/hide)

white Kd2 Sg1 Rh1 black Kg5 Ba1 Pa2d4g3

-8 & s#1    Proca Retractor       (3+5)
Anti-Circe


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Dirk Borst
Dirk Borst
April 15, 2017 20:15

This appears to be cooked: 1.Kd2-c2 Ba1-c3+ (Bb2-c3+ goes quicker) 2.Sb1xPc3->g1 c4-c3+ 3.Ke3-d2 d5-d4+ 4.Kd4-e3 a2-a1B+ 5.Ke4-d4 d7/d6-d5+ 6.f7xQ/Re8=S->b1 and 1.Kf5+ Q/Re1# or am I missing something!?

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