No.1185 |
Original Fairy problems |
Definitions: (click to show/hide)
Maximummer: Black must play the geometrically longest move or may choose from among longest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagora’s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply.
Circe Equipollents: After a piece is captured, it is immediately replaced on the square which is the same distance and direction from the square of its capture, as was that square from the square upon which its captor commenced its move. (If Qf7 captures a Pawn on e7, it is reborn on d7, because d7 is a same distance and direction from e7 as e7 is from f7. Similarly, if Qg7 captures a piece on ‘e7’ its rebirth square is ‘c7’). If the rebirth square is occupied the captured piece disappears
Minimummer: Black must play his geometrically shortest move or may choose from among shortest moves of equal length, distances being measured from the center of each square. Diagonal and oblique distances are measured from the orthogonal coordinates by using Pythagoras’s s theorem (take the square root of the sum of the squares of the orthogonal distances). All other orthodox chess rules apply. White Minimummer: White must make moves with minimal possible length.
Marguerite (MG): Moves like all simple hoppers (eagle + grasshopper + hamster + moose + sparrow).
Grasshopper (G): Moves along Q-lines over another unit of either color to the square immediately beyond that unit. A capture may be made on arrival, but the hurdle is not affected.
Eagle (EA): A grasshopper which pivots 90 o (to either side) at the hurdle.
Hamster (HA): Moves like a Grasshopper but deflect 180o on passing over the hurdle.
Moose (M): A grasshopper which pivots 45 o (to either side) at the hurdle.
Sparrow (SW): A grasshopper which pivots 135 o (to either side) at the hurdle.
No.1185 Erich Bartel |
Solution: (click to show/hide) |
white kh1
black gh3 mgh4
hs#10* (1+2) |
1...MGh4-g2 2.Kh1-g1 Gh3-f1 + 3.Kg1*f1[+bGe1] MGg2-e2 + 4.Kf1-g1 Ge1-h1 5.Kg1-g2 MGe2-h3 + {
} 6.Kg2-f2 Gh1-h4 7.Kf2-f1 MGh3-e1 8.Kf1-f2 MGe1-g3 + 9.Kf2-f1 Gh4-f2 #
1.Kh1-g1 MGh4-g2 2.Kg1-h1 Gh3-f1 3.Kh1-h2 Gf1-h3 + 4.Kh2*h3[+bGh4] MGg2-g4 + 5.Kh3-h2 Gh4-h1 {
} 6.Kh2-g2 MGg4-f1 + 7.Kg2-g3 Gh1-e1 8.Kg3-h3 MGf1-h4 9.Kh3-g3 MGh4-f2 + 10.Kg3-h3 Ge1-g3 # {
(C+ by Popeye 4.75)}
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