No.1699
Borisas Gelpernas
(Lithuania)

Original Fairy problems
JF-2022-I:
01.01.2022 - 30.06.2022


Definitions / Определения


No. 1699 Borisas Gelpernas
Lithuania
original - 09.04.2022

black Rd3d8 Pb2g4h2g7 Bh3f8 Kh8 Sg8 white Kb5 Pe7
h#2            2 solutions            2+10
Breton Adverse

Solution: (click to show/hide)


Subscribe
Notify of
guest
2 Comments
Oldest
Newest Most Voted
Inline Feedbacks
View all comments
Geoff Foster
Geoff Foster
April 10, 2022 01:12

The problem is sound without bRd3. Also, the only function of bBh3 is to stop 1.h1=Q exd8=S 2.Qh7 Sf7#. In fact, removing bRd3, bBh3 and bPb2 gives a more interesting problem, with solutions:
 1.h1=Q exd8=S 2.Qh7 Sf7#
 1.h1=R exf8=S 2.Rh7 Sg6#

Joost de Heer
Joost de Heer
April 10, 2022 14:50
Reply to  Geoff Foster

You can also remove Pg4 in your version.